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3 years ago

Neeeeeed helllllpppp

Mathematics

2 answers:

fredd [130]3 years ago

6 0

Hopefully you can see it

tester [92]3 years ago

4 0

Your answer is:
u = x + 3

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What is -7/ 12 plus 7/10 in simplest form

VMariaS [17]

It would be: -7/12 + 7/10 = -35+42 /60 = 7/60

So, your final answer is 7/60

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3 years ago

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A city phone book has 86 pages filled with residents names. There are a total of 15.050 names in the book. Eachpage has an equal

Vsevolod [243]

There are 175 names on each page.

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3 years ago

Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

ANSWER:

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

SOLUTION:

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$

Hence the x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

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2 years ago

Is the ordered pair (-2, 1) a solution to the equation - 3x + y = 5? No Yes

Otrada [13]

Answer:

Step-by-step explanation:

Plug (-2,1) into -3x+y=5. This will make it -3(-2)+(1)=5. This is equal to 6+1=5. 7=5. 7 is not equal to 5. Therefore, (-2,1) is not a solution to the equation -3x+y=5.

If this helps please mark as brainliest

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3 years ago

The length of the two sides of the right triangle ABC are given.Find the length of the missing side.See example 1

vitfil [10]

The answer is 10. Hope this helps.

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3 years ago

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