Answer:
9+11s
Step-by-step explanation:
9+18s-7s
=9+11s
You can't add 9 and 11s because they are different variables
To find the zeros of this function, we must first set the entire function equal to 0
f(x) = x² - 2x - 15 = 0
Since this is a quadratic function, we must use the quadratic formula, which is:

Let's assign a, b, and c using our first function
x² means a = 1 (because it could be written as 1x²)
-2x means b = -2
-15 means c = -15
Now let's plug those in:

which simplifies to:

Simplified further:


And divide it by the 2 on the bottom gives us:

2+4 = 6
2-4 = -2
So the zeros of this function are
-2 and
6
If you observe the graph, the graph is touching the x-axis at the point x=-1 and is turning away.
This means, the graph as an even multiplicity at x=-1. So the two roots of the given polynomial are x = -1 and x = -1. Thus, the two factors of the polynomial are (x+1) and (x+1)
Product of the factors is equal to the polynomial. So the given polynomial will be (x+1)(x+1).
Therefore, the answer to this question is option C
Answer:
30
Step-by-step explanation:
5+2/3x=25
2/3x=25
x=25/(2/3)
x=30