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3 years ago

6

Help now fast please

1 answer:

Vsevolod [243]3 years ago

8 0

2y64xxy43x686ex4226xe

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Solve the equation. (find x)

Irina-Kira [14]

Answer:

Step-by-step explanation:

$(x^2-3x+1)^{(2x^2+x-6)}=1\ we \ take \ the \ logarithm\\\\(2x^2+x-6)*ln(x^2-3x+1)=0\\\\(2x^2+x-6)=0\ or\ x^2-3x+1=1\\\\1)\\2x^2+x-6=0\\2x^2+4x-3x-6=0\\2x(x+2)-3(x+2)=0\\(x+2)(2x-3)\\x=-2\ or\ x=\dfrac{3}{2} \\\\2)\\x^2-3x=0\\x(x-3)=0\\x=0\ or\ x=3\\\\sol=\{-2,0,\dfrac{3}{2},3\}\\$

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3 years ago

-9(6+u)-2u= -10 HELPPPP

Fed [463]

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Step-by-step explanation:

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3 years ago

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Which number sentence is true? A. 3.4 x (-3.4) = 11.56 B. 3.4 x 3.4 = 11.56 C. -3.4 x (-3.4) = -11.56 D. -3.4 x 3.4 = 11.56

avanturin [10]

answer b is true 3.4x3.4 = 11.56

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3 years ago

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balu736 [363]

Answer:

slope = 1

Step-by-step explanation:

-3 | -3

5 | 5

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8 | 8

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3 years ago

Find the product.<br><br> 2a2(5b2+3ab+6a+1)<br><br> PLEASE HELP!!!! ASAP!!!

Anon25 [30]

Answer:

$10a^{2} b^{2} +6a^{3} b+12a^{3} +2a^{2}$

Step-by-step explanation:

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3 years ago

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