By the Pythagorean theorem
50^2 = x^2 +(x +34)^2
2500 = 2x^2 +68x + 1156
x^2 +34x -672 = 0
(x -14)(x +48) = 0
x = 14 or -48
The distance from the wall to the base of the ladder is 14 ft.
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7-24-25 is a Pythagorean triple. The dimensions here are double those values. It can be handy to know a few of the Pythagorean triples, as that can let you write down the answers to problems without having to go through the equations.
132min=2h 12min
15:35 + 2h 12min=17:47
9514 1404 393
Answer:
after 7 minutes
19,600 feet
Step-by-step explanation:
Here's the "pencil and paper" solution:
The two altitude equations are ...
y = 41300 -3100x
y = 2800x
They can be solved by setting the expressions for y equal to each other.
2800x = 41300 -3100x
5900x = 41300
x = 41300/5900 = 7
y = 2800·7 = 19600
The planes will both be at 19,600 feet after 7 minutes.
Answer:
1. Write the following as a mixed number.
2. Write as an improper fraction
3. Perform the operation and write the answer in simplest form.
a)4/7*3/11= 12/77
b)6/10 / 12/7= 7/20
c)5 1/7*3 1/9= 16
d)6 3/7 / 1 13/14= 10/3
Hope this helps
Step-by-step explanation:
Step-by-step explanation:
5x+52=9x+20
subtract 5x on both sides
subtract 20 on both sides
32=4x
divide by 4 on both sides
x=8
plug in x to the equations for A, D, and C
A and D are 92°
C is 56°
B and C will add up to 90, so
90-56=34°
13y-6=34
add 6 on both sides
13y=40
divide by 13
y=40/13 (I don't wanna calculate that)
