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docker41 [41]
2 years ago
4

Use the periodic table to identify each of the elements below as an alkali metal

Chemistry
1 answer:
Neporo4naja [7]2 years ago
3 0

\huge{ \mathfrak{\underline{question  : }}}

Use the periodic table to identify each of the elements below as an alkali metal or an alkaline earth metal.

Rb = Rubidium

\huge{ \mathfrak{\underline{Answer :  }}}

Rubidium (Rb) is an Alkali metal.

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Explain why energy has to be supplied to turn a liquid into a gas
jeka94

Answer:

heat energy are absorbed by water molecules and it is used to change the molecules from liquid to gas? if thats what your asking.

Explanation:

7 0
2 years ago
How many atoms of nitrogen are present in 2.49 moles of nitrogen trifluoride ? atoms of nitrogen?
stepladder [879]
<span>Nitrogen trifluoride - NF3.
1 mol NF3 contains 1 mol atoms of Nitrogen
2.49 mol NF3 contains 2.49 mol atoms of Nitrogen

1 mol   ----  6.02 *10²³ atoms
2.49 mol ----- 2.49*6.02*10²³ = 15.0*10²³ atoms of N</span>
6 0
2 years ago
The density of air under ordinary conditions at 25°C is 1.19 g/L. How many kilograms of air are in a room that measures 10.0 ft
Lunna [17]

Answer: The mass of air present in the room is 37.068 kg

Explanation :  Given,

Length of the room = 10.0 ft

Breadth of the room = 11.0 ft

Height of the room = 10.0 ft

To calculate the volume of the room by using the formula of volume of cuboid, we use the equation:

V=lbh

where,

V = volume of the room

l = length of the room

b = breadth of the room

h = height of of the room

Putting values in above equation, we get:

V=10.0ft\times 11.0ft\times 10.0ft=1100ft^3=31148.53L

Conversion used : 1ft^3=28.3168L

Now we have to calculate the mass of air in the room.

Density=\frac{Mass}{Volume}

1.19g/L=\frac{Mass}{31148.53L}

Mass=37066.7507g=37.068kg

Conversion used : (1 kg = 1000 g)

Therefore, the mass of air present in the room is 37.068 kg

3 0
2 years ago
Read 2 more answers
The solubility of N2 in water at a particular temperature and at a N2 pressure of 1 atm is 6.8 × 10–4 mol L–1. Calculate the con
grin007 [14]

Answer:

The correct answer is 5.30 * 10^-4 mol per L.

Explanation:

Based on Henry's law, in a solution solubility of the gas is directly proportional to the pressure, that is, C is directly proportional to P. Here P is the pressure and C is the concentration of the dissolved gases.  

Therefore, it can be written as,  

C2/C1 = P2/P1

Here, C1 is 6.8 * 10^-4 mol/L, P1 is 1 atm and P2 is 0.78 atm, then the value of C2 obtained by putting the values in the equation,  

C2/(6.8*10^-4) = 0.78/1

C2 = 0.78 * 6.8*10^-4

C2 = 5.30 * 10^-4 mol per L.  

Hence, the concentration of dissolved nitrogen at 0.78 atm is 5.30*10^-4 mol/L.  

7 0
2 years ago
What is a pure substance
Semmy [17]
A pure substance is a element made up of only one type of atom or molecule.
6 0
3 years ago
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