Answer: true
Explanation: i think its true
To calculate the concentration of the base based on the titration, the concept used is the equal of number of equivalence of the acid used to that of the base. From this,
Na x Va = Nb x Vb
For HBr and KOH, molarity is equal to normality. Substituting the known values,
(0.75 M) x (22.6 mL - 0 mL) = Nb x (37.5 mL - 0.5 mL)
Nb = 0.46 N
Mb = 0.46 M
Thus, the concentration of the base is approximately 0.46 M.
Answer:
5.23 moles of C₁₀H₈N₂O₂S₂
Explanation:
In order to find the moles of dipyrithione we need to know its formula:
C₁₀H₈N₂O₂S₂
1 mol of N contains 6.02×10²³ atoms
We need to find out the moles of 6.3×10²⁴ atoms of N
6.3×10²⁴ atoms . 1 mol /6.02×10²³ atoms = 10.4 moles of N
Therefore, we know that 1 mol of dipyrithione has 2 moles of N, so we need to make this rule of three:
2 moles of N are contained in 1 mol of C₁₀H₈N₂O₂S₂
10.4 moles of N must be contained in (10.4 . 1) /2 = 5.23 moles of C₁₀H₈N₂O₂S₂
