Question

What would be the pH of an H2SO4 solution if the [H+] = 4.58 x 10-5 moles/liter?

Answer 1

Answer: pH of an $H_2SO_4$ solution is 4.34

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

$pH=-\log [H^+]$

$H_2SO_4\rightarrow 2H^++SO_4^{2-}$

Putting in the values:

$pH=-\log[4.58\times 10^{-5}]$

$pH=4.34$

Thus pH of an $H_2SO_4$ solution if the $[H^+]$ is $4.58\times 10^{-5}]$ is 4.34