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3 years ago

Identify, and briefly explain, two key elements needed for fossilization.Please Help Me!!!

Chemistry

2 answers:

Yakvenalex [24]3 years ago

7 0

Body elements and trace fossils I believe

Natali [406]3 years ago

4 0

Answer:

When plant or animals after being alive are preserved in sedimentary rocksis called "taphonomy" or fossilization; when they die in a watery environment, and after soft tissues are decomposed, the hard body parts such as shells and bones are turned into a mold when the sediments harden over time.

High pressure is key to generate the mineralization.

Anoxic preservation is also key, which is the condition of being shielded and safe from oxygen to avoid erosion or corrosion.

And of course, the entity must contain hard body parts that could linger over time.

Explanation:

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Answer:

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2 years ago

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Use the Ref An aqueous solution of chromium(II) acetate has a concentration of 0.260 molal. The percent by mass of chromium(II)

poizon [28]

Answer:

The percent by mass of chromium(II) acetate in the solution is 4.42%.

Explanation:

Molality of the chromium(II) acetate solution = 0.260 m = 0.260 mol/kg

This means that in 1 kg of solution 0.260 moles of chromium(II) acetate are present.

1000 g = 1 kg

So, in 1000 grams of solution 0.260 moles of chromium(II) acetate are present.

Then in 100 grams of solution = $\frac{0.260 mol}{1000}\times 100=0.0260 mol$

Mass of 0.0260 moles chromium(II) acetate:

= 0.0260 mol × 170 g/mol = 4.42 g

$(w/w)\%=\frac{\text{mass of solute in 100 gram solution}}{100}\times 100$

$=\frac{4.42 g}{100 g}\times 100=4.42\%$

The percent by mass of chromium(II) acetate in the solution is 4.42%.

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3 years ago

Calcium hypochlorite (ca(ocl)2, mw = 142.983 g/mol) is often used as the source of the hypochlorite ion (ocl–, mw = 51.452 g/mol

stiv31 [10]

When the concentration is expressed in ppm, that means parts per million. It is also equivalent to mg/L. For this problem, we do stoichiometric calculations. We manipulate the units by cancelling like units if they appear in the numerator and denominator side until we come with the amount of solid Ca(OCl)2 needed. The solution is as follows:

40 mg/L * (1 L/1000 mL) * 50 mL * (1 g/1000 mg) * (1 mol OCl⁻/51.452 g) * (1 mol Ca(OCl)₂/ 2 mol OCl⁻) * (142.983 g Ca(OCl)₂/mol) * 0.95 = 2.64×10⁻3 g or 2.64 mg.

Therefore, you would need 2.64 mg of solid Ca(OCl)₂.

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4 years ago

A plant uses carbon dioxide and water to form food and oxygen. Why is this a chemical change?

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Answer:

D. The properties of carbon dioxide and oxygen are different.

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3 years ago

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Answer:

the nuclear envelope disappears

Explanation:

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3 years ago

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