Answer:
![r = k . [CO] .[Cl_{2}]](https://tex.z-dn.net/?f=r%20%3D%20k%20.%20%5BCO%5D%20.%5BCl_%7B2%7D%5D)
Explanation:
Let´s consider the following reaction:
CO + Cl₂ ⇒ COCl₂
The general rate law is:
![r = k . [CO]^{m}. [Cl_{2}]^{n}](https://tex.z-dn.net/?f=r%20%3D%20k%20.%20%5BCO%5D%5E%7Bm%7D.%20%5BCl_%7B2%7D%5D%5E%7Bn%7D)
where,
r is the rate of the reaction
k is the rate constant
[CO] and [Cl₂] are the molar concentrations of each reactant
m and n are the reaction orders for each reactant
Since the reaction is first order in CO, m = 1. The overall order is the sum of all the individual orders. In this case, the overall order m + n = 2. Then,
m + n = 2
n = 2 - m = 2 - 1 = 1
The reaction is first order in Cl₂.
The rate law is:
![r = k . [CO]. [Cl_{2}]](https://tex.z-dn.net/?f=r%20%3D%20k%20.%20%5BCO%5D.%20%5BCl_%7B2%7D%5D)
Answer:
2.268 L
Explanation:
According to Ideal Gas Law, " The Volume of a given mass of gas is inversely proportional to the applied Pressure and directly proportional to applied temperature, ". Mathematically the initial and final states of gas are given as,
P₁ V₁ / T₁ = P₂ V₂ / T₂ ----------- (1)
Data Given;
P₁ = 0.998 atm
V₁ = 2.1 L
T₁ = 36 °C = 309 K
P₂ = 0.90 atm
T₂ = 28 °C = 301 K
V₂ = ??
Solving equation 1 for P₂,
V₂ = P₁ V₁ T₂ / T₁ P₂
Putting values,
V₂ = (0.998 atm × 2.1 L × 301 K) ÷ (309 K × 0.90 atm)
V₂ = 2.268 L
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I hope this will help.
