There is a rule in naming polyatomic anions containing oxygen. Those names ending in –ate are given to the most common oxyanion of an element. While those names ending in –ite are for those that contains fewer O atom for the same charge. Since P $PO_{3} ^{3-}$ has fewer O atoms, its name ends in –ite. Thus, P $PO_{3} ^{3-}$ is phosphite while P $PO_{4} ^{3-}$ is phosphate.

4 0

2 years ago

How many grams of barium sulfate, BaSO 4 , be precipitated when 2.25 moles of sodium sulfate , Na 2 SO 3 , reacts with an excess

gulaghasi [49]

Answer:

525.1 g of BaSO₄ are produced.

Explanation:

The reaction of precipitation is:

Na₂SO₄ (aq) + BaCl₂ (aq) → BaSO₄ (s) ↓ + 2NaCl (aq)

Ratio is 1:1. So 1 mol of sodium sulfate can make precipitate 1 mol of barium sulfate.

The excersise determines that the excess is the BaCl₂.

After the reaction goes complete and, at 100 % yield reaction, 2.25 moles of BaSO₄ are produced.

We convert the moles to mass: 2.25 mol . 233.38 g/mol = 525.1 g

The precipitation's equilibrium is:

SO₄⁻² (aq) + Ba²⁺ (aq) ⇄ BaSO₄ (s) ↓ Kps

7 0

2 years ago

Find the volume of 56.0 grams of O2

N76 [4]

Answer:

39.2 L at STP

Explanation:

Convert the grams to moles first by dividing 56.0 by the molar mass of O2 (32.0) then convert to volume by multiplying by 22.4.

= 39.2 L

5 0

2 years ago