1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nesterboy [21]
3 years ago
14

Calculate the hydronium ion concentration in an aqueous solution with a pH of 11.7 at 25°C.

Chemistry
1 answer:
DENIUS [597]3 years ago
6 0

Answer:

Approximately 2\times 10^{-12}\;\rm mol \cdot L^{-1}.

Explanation:

The hydronium ion concentration \left[\mathrm{H_3O^{+}}\right] of an aqueous solution can be found from its \rm pH with the equation:

\displaystyle \left[\mathrm{H_3O^{+}}\right] = 10^{-\mathrm{pH}}.

For this solution, \rm pH= 11.7. Hence,

\begin{aligned}& \left[\mathrm{H_3O^{+}}\right] \\ &= 10^{-\mathrm{pH}} \\ &= 10^{-11.7} \approx 2 \times 10^{-12}\end{aligned}.

Note that for this equation, the number of significant figures in \left[\mathrm{H_3O^{+}}\right] should be the same as the number of decimal places in \rm pH. For example, the \rm pH of this question comes with only one decimal place. As a result, there would be only one significant figure in the \left[\mathrm{H_3O^{+}}\right] obtained from the equation.

You might be interested in
32 POINTS!!!!
krok68 [10]
1. statement
2. b
3. a
8 0
3 years ago
Read 2 more answers
We dissolve 93 grams of sodium sulfate (Na2SO4) in 20 grams of water. What is the percent by mass of sodium sulfate in this solu
dlinn [17]
It should be for the total solution of 93 plus 20 grams which is 113 grams so 93 divided by 113 grams comes to 82.3% sodium sulfate and this can be checked by multiplying 113 grams by 0.823 which results in 93 grams of sodium sulphate. 
4 0
3 years ago
Suppose NAD is unavailable because NADH cannot be oxidized due to a mutation in the NADH dehydrogenase (Complex I). If FAD could
Dovator [93]

Answer:

FAD substitution will produce 28 ATP instead of 36.

Explanation:

NAD and FAD are coenzymes involved in reversible oxidation and reduction reactions. These compounds are also known as electron carriers. However NADH produce 3 electrons in electron transport chain and FADH2 produce 2 electron beacuase it transfer the electrons to second complex in ETC.

Normal prduction of ATP from glucose;

2 cytoplasmic NADH formed in glycolysis         Each yields 2 ATP   +4

2 NADH formed in the oxidation of pyruvate Each yields 3 ATP         +6

2 FADH2 formed in the citric acid cycle         Each yields 2 ATP         +4

6 NADH formed in the citric acid cycle             Each yields 3 ATP         +18

2 ATP from glycolysis                                                                                   +2  

2 ATP from citric acid cycle                                                                          +2                            

                                                                    Net yield ATP +36

C6H12O6 + 6 CO2 + 36 ADP + 36 Pi ⇒6 CO2 + 6 H2O + 36 ATP

If we replace the NAD with FAD the total ATP production would be.

2 cytoplasmic FADH2 formed in glycolysis          Each yields 2 ATP            +4

2 FADH2 formed in the oxidation of pyruvate   Each yields 3 ATP    +4

2 FADH2 formed in the citric acid cycle            Each yields 2 ATP    +4

6 FADH2 formed in the citric acid cycle                  Each yields 2 ATP   +12

2 ATP from glycolysis                                                                                    

+2

2 ATP from citric acid cycle                                                                            +2

                                                                  <u>Net yield ATP +28</u>

C6H12O6 + 6 CO2 + 28ADP + 28 Pi ⇒6 CO2 + 6 H2O + 28 ATP

7 0
3 years ago
How much volume would a 834.01g pile of sugar have given that it has a density of 1.59g/mL?
boyakko [2]

Answer:

v = 534.5mL

m = 597.15g

Density = 9.23g/mL

Density = 9.125g/mL

Explanation:

Density = mass/ volume

For the first question

Density = 1.59g/mL

Mass = 834.01g

Volume = ?

Using the above formula we have 1.59 = 834.01/v

v = 834.01/1.59

v = 534.5mL

For the second question

Density =0.9167g/mL

Volume = 651.41mL

Mass =?

Using the above formula we have

0.9167 =m/651.41

Cross multiply

m = 0.9167 x 651.41

m = 597.15g

For the third question

Mass =803.44g

Volume=87.03mL

Density =?

Density = 803.44/87.03

= 9.23g/mL

For the fourth

Density = 56.85/6.23

= 9.125g/mL

7 0
3 years ago
"calculate the ratio of the velocity of hydrogen molecules to the velocity of carbon dioxide molecules at the same temperature"
Ne4ueva [31]

Answer: 1:4.69

Explanation:

The ratio can be expressed as:

Ua/Ub= √(Mb/Ma)

Where Ua/Ub is the ratio of velocity of hydrogen to carbon dioxide and Ma is the molecular mass of hydrogen gas= 2

Mb is the molecular mass of CO2 = 44

Therefore

Ua/Ub= √(44/2)

Ua/Ub = 4.69

Therefore the ratio of velocity of hydrogen gas to carbon dioxide = 1:4.69

which implies hydogen is about 4.69 times faster than carbon dioxide.

8 0
3 years ago
Other questions:
  • When the volume of a gas is changed from mL to 852 mL the temperature will change from 315c to 452c
    6·1 answer
  • A solution of 3 moles of carbon disulfide in 10 moles of ethyl acetate has a vapor pressure of 170 torr at 28°c. the vapor press
    11·1 answer
  • How are refraction and diffraction similar? How are they different? Check all that apply. Refraction and diffraction both involv
    15·2 answers
  • If 200.0 g of copper(II) sulfate react with an excess of zinc metal, what is the theoretical yield of copper?
    6·2 answers
  • Suppose you analyze the composition of an unnamed compound. Your analysis shows that
    10·2 answers
  • Charles Lyell believed that:
    10·1 answer
  • At 20 degrees Celsius, the density of air is 1.20 g/L. Nitrogen's density is 1.17 g/L. Oxygen's density is 1.33 g/L. Will balloo
    12·2 answers
  • Suppose you had 2.0158 grams of hydrogen (H2).
    9·1 answer
  • GUYS I NEED HELP WITH THIS ASSIGNMENT MY LAST ASSIGNMENT FOR THE DAY
    5·1 answer
  • How many moles are equal to 8.44 x 1023 atoms of sulfur?
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!