Answer:
There is 5.56 g of gold for every 1 g of chlorine
Explanation:
The question is to determine the simplest mass ratio of gold to Chlorine in the compound.
Since the mass of gold in the compound compared to chlorine is 15.39 g for every 2.77 g, the mass of gold per gram of chlorine is given as:
15.39 / 2.77 = 5.56 g of gold to two decimal places
<em>Therefore, for every 5.56 g of gold, there is 1 g of chlorine.</em>
<em>Note : The ratio in which different elements combine by mass to form a compound is given by the law of constant composition which states that, "all pure samples of a particular chemical compound contain the same elements combined in the same proportion by mass.</em>
Using Gay-Lussac's Law, pressure is proportional to (absolute) temperature in Kelvin. We first convert the temperature values to Kelvin: 110 C = 383.15 K, while 65 C = 338.15 K.
P1/T1 = P2/T2
22.5/383.15 = P2/338.15
P2 = 19.9 psi
<span>A. Commercial cooking
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Aluminum. chemical element with symbol Al
Freezing rain is the term given to the precipitation of the rain sustained at temperatures below freezing by the ambient air mass, which results in freezing on encountering with the surfaces. Freezing rain is formed completely of liquid droplets, unlike sleet, ice pellets, or hail.
The freezing rain falls and solidifies on a wire fence as the rain is changing from a liquid to a solid state by withdrawing thermal energy, ultimately resulting in freezing.
