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dezoksy [38]
3 years ago
6

How do u stop whaching adds if ur new

Mathematics
2 answers:
Alexxx [7]3 years ago
6 0

Answer:

to be honest I dont know

Step-by-step explanation:

I dont know  how.

faust18 [17]3 years ago
3 0

Answer:

i dont know honestly  i crated account then it stooped it for me

Step-by-step explanation:

You might be interested in
Two students use different methods to solve this multiplication problem: 25⋅-155825·-1558 read each of their methods below and t
melisa1 [442]

Answer: The answer in simplest form is -6(1/4)

Step-by-step explanation:

In Wyatt's method I observed the mixed fraction was converted to simple fraction in the second step.

Therefore Wyatt's solution will be:

2/5 * -15(5/8) = 2/5 * -125/8 = -25/4

Distributive property was used in Abigail's method.

The solution would be:

2/5 * -15(5/8) = 2/5(-15 -5/8) = 2/5(-15) + 2/5(-5/8) = -6(-1/4)

Note: Complete question is contained in the image

3 0
3 years ago
Read 2 more answers
Use inverse operations to solve h/3-8 explain each step to thx so much for your help! :{)
lara [203]
  <span>So you have to break it down by steps. For the first one19= h over 3-8. First what's 19+8, which is 27. So if you forget the minus 8 part, the answe has to equal 27. 27 x 3 is 81. So if we plug the numbers in, 19= 81/3 -8 makes sense. For the second one, 5t+8= 43. 43- 8 is 35. What times 5 is 35, that's 7. So plug it in, 5x7 +8 = 43. 
Hope it makes sense now!!</span>
3 0
4 years ago
Read 2 more answers
Please help me someone
posledela
To solve this, you need to know three exponent rules:
1) Power of a product
Basically says (ab)^{2} =  a^{2}  b^{2}. This means a product raised to a power is the same as taking each factor to that power and multiplying them.

For example: (5a)^{2}  = 5^{2} a^{2}

2) Product of powers
Basically says a^{m}  a^{n} =  a^{m+n}. When two expressions with the same base (a) are multiplied, you can add their exponents while keeping the same base.

For example: a^{2}  a^{3} = a^{2+3} =  a^{5}

3) Power of a power
Basically says (a^{m})^{n} =  a^{m \times n}. When an exponent is being raised to a exponent, you can multiply the exponents.

For example: (a^{2})^{3} = a^{(2 \times 3)} =  a^{6}
----

Back to your problem:
You are asked to simplify (6x^{2} y)^{2} (y^{2})^{3}, Tackle it by simplifying both factors and then multiplying them together and simplifying again.

1) First use the power of a product rule to change (6x^{2} y)^{2} into 6^{2}  (x^{2})^{2}  y^{2}. Simplify it into &#10;36 x^{4}  y^{2} using the power of a power rule.

2) Simplify (y^{2})^{3} into y^{6} using the power of a power rule.

3) Multiply the simplified factors from part one and two and simplify using the product of powers rule:
(36 x^{4} y^{2})(y^{6})\\&#10;= (36 x^{4})(y^{2} y^{6})\\&#10;= (36 x^{4})(y^{2+6}) \\&#10;= 36 x^{4}y^{8}

---

Answer: 36 x^{4}y^{8}
6 0
4 years ago
2/8+3/6 what is it?? help​
AleksAgata [21]

2/8+3/6 = 0.75 or 3/4

7 0
3 years ago
Read 2 more answers
I NEED HELP PLEASE ASAP !
In-s [12.5K]

The first rule you need to know is

(a^b)^c=a^{bc}

So, you have

\dfrac{(x^{25})^{-6}}{(x^{-3})^{48}}=\dfrac{x^{25\cdot(-6)}}{x^{-3\cdot 48}}=\dfrac{x^{-150}}{x^{-144}}

The second rule you need to know is

\dfrac{a^b}{a^c}=a^{b-c}

So, you have

\dfrac{x^{-150}}{x^{-144}}=x^{-150-(-144)}=x^{-150+144}=x^{-6}

4 0
4 years ago
Read 2 more answers
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