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3 years ago

14

There is 1 worker for every 5 children. There are 105 children at the center. What is the proportion to find x, the number of wo

rkers?

1 answer:

Licemer1 [7]3 years ago

7 0

1:5 is not the answer, the answer is actually x=21 since 1 worker is to every 5 children (1:5) and 105 divided by 5 equals 21.

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Find the stated lengths in each parallelogram

alexandr1967 [171]

Answer:

40/3, 172/3, respectively

Step-by-step explanation:

x + 9 = 2y

2x = 2y + 2

x + 9 = 2(2x - 2)

4x - 4 = x + 9

3x - 13 = 0

x = 13/3

y = 40/6

RT = 13/3 + 9 = 40/3

QS = 160/3 + 4 = 172/3

8 0

3 years ago

There are two numbers such that , if both of them are individually increased by 5 and then by the same percentage as they were i

QveST [7]

Let the two numbers be x and y.
Let m = the fraction (or percentage) for increasing the numbers.

Increase x by 5, multiply (x+5) by (1+m), and set it qual to 36.
(x + 5)*(1 + m) = 36

Increase y by 5, multiply (y+5) by (1+m), and set it equal to 36.
(y+5)*(1+m) = 36

Therefore
(x+5)*(1+m) = (y+5)*(1+m)
x + 5 = y + 5
x = y
x - y = 0

Answer: 0.
The difference between the two numbers is zero.

5 0

4 years ago

Multiply this expression :: -2/7 • (-3 5/8)

Helen [10]

Answer: 29/28

Step-by-step explanation:

-2/7 x (-3 5/8)

= -2/7 x -29/8

= 2/7 x 29/8 = 1/7 x 29/4

= 29/28

7 0

3 years ago

Use the coordinate plane to plot the points (6, 0) and (0, 5). Which statement is true? (0, 5) is located on the x-axis. (0, 5)

m_a_m_a [10]

Answer:

(6, 0) is located on the x-axis

Explanation:

For a point to be on the x-axis, its y-value must equal 0. (6, 0) has an x-value of 6 and a y-value of 0.

"(0, 5) is located at the origin" is not true because the origin is at (0, 0).

"(0, 5) is located on the x-axis" is not true because its y-value is 5, not 0.

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6 0

3 years ago

Without a calculator how would you solve this?

mina [271]

Answer:

the largest number that is less than (2+√3)^6 is 2701

Step-by-step explanation:

$\bigstar \ (2+\sqrt{3})^6= \\\\C{}^{0}_{6}2^{6}+C{}^{1}_{6}2^{5}\sqrt{3}^1+C{}^{2}_{6}2^{4}\sqrt{3}^2+C{}^{3}_{6}2^{3}\sqrt{3}^3+C{}^{4}_{6}2^{2}\sqrt{3}^4+C{}^{5}_{6}2^{1}\sqrt{3}^5+C{}^{6}_{6}\sqrt{3}^6$

$=64+192\sqrt{3}+720 +480\sqrt{3} +540+108\sqrt{3} +27\\=1351+780\sqrt{3}$

$\bigstar\ (2-\sqrt{3} )^6 =\\\\1351-780\sqrt{3}$

$\bigstar\ \bigstar\ (2+\sqrt{3} )^6+(2-\sqrt{3} )^6 =\\\\1351+780\sqrt{3}+1351-780\sqrt{3}$

$\Longrightarrow(2+\sqrt{3} )^6+(2-\sqrt{3} )^6 =2702$

$\Longrightarrow(2+\sqrt{3} )^6 =2702-(2-\sqrt{3} )^6$

$0 < \left( 2-\sqrt{3} \right) < 1 \Longrightarrow 0 < \left( 2-\sqrt{3} \right)^{6} < 1 \Longrightarrow-1 < \left( 2-\sqrt{3} \right)^{6} < 0$

$\Longrightarrow2702-1 < 2702-\left( 2-\sqrt{3} \right)^{6} < 2702+0$

$\Longrightarrow 2701 < \left( 2+\sqrt{3} \right)^{6} < 2702$

8 0

2 years ago