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horsena [70]
4 years ago
5

What is the value of x?​

Mathematics
1 answer:
Lorico [155]4 years ago
8 0

Answer:

Option A = 6

Step-by-step explanation:

3x- 5 = x+ 7           ( as diagonals r equal in a recangle)

3x-x = 7+ 5

2x = 12

x = 12/ 2 = 6

I hope im  Right !!

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140 fluid ounces increased by 45%
Stels [109]
Hello!

"Increase" means to add. We must find out what 45% of 140 fluid ounces is, and to do that we must first convert the percentage to a decimal and then multiply it by the amount of fluid ounces.

I know, that's probably a lot to take in! :D

45% ÷ 100 = 0.45 as a decimal

0.45 × 140 = 63

Add this to the amount of fluid ounces:

140 + 63 = 203

Final Answer:

203 fluid ounces.
5 0
3 years ago
Read 2 more answers
Stephanie took a science exam that had two parts.
patriot [66]

Answer:

44 questions

Step-by-step explanation:

Part 1: She got 16 questions correct, which was 4/5 of the number of part 1 questions.

Let x = total number of questions in part 1

4/5x = 16

Divide both sides by 4/5

x = 16 ÷ 4/5

= 16 × 5/4

= 20

x = 20

There are 20 questions in part 1

She got 16 questions correct, which was 2/3 of the number of part 2 questions.

Let y = number of questions in part 2

2/3y = 16

Divide both sides by 2/3

y = 16 ÷ 2/3

= 16 × 3/2

= 24

y = 24

There are 24 questions in part 2

The total number of questions on Stephanie’s exam = part 1 + part 2

= 20 + 24

= 44 questions

8 0
3 years ago
Find the measurement indicated in each parallelogram.<br> VH=3x+4<br> VX=7x+3<br> find VX
kondaur [170]
I’m a complete parallelogram
6 0
3 years ago
The table shows four account transactions. Find the account balance after the transactions when the account started with a balan
Sveta_85 [38]

Answer:

90

Step-by-step explanation:

6 0
3 years ago
A) If a:b = 2:5 and b:c = 3:4, find (i) a:c(ii) a:b:c
kobusy [5.1K]

Answer:

A i. a:c=3:10

ii. a:b:c=2:5:10

B i. x:z=2:5

ii. x:y:z=2:4:5

Step-by-step explanation:

A.) If a:b = 2:5 and b:c = 3:4, find (i) a:c(ii) a:b:c

a:b=a/b=2/5

b:c=b/c=3/4

a/b*b/c=a/c

2/5*3/4=a/c

6/20=a/c

3/10=a/c

Therefore, a:c=3:10

a:b:c

a:b=2:5

b:c=3:4

b is common to both ratios

The value of b in the first ratio is 5 and b is 3 in the second ratio

Lets take the LCM of both values

LCM of 5 and 3=15

So, we will change the value of b in the first ratio and second ratio to 15

By doing this, we will multiply the whole first ratio by 3

We have, 6:15

We multiply the whole second ratio by 5

We have, 15:20

Therefore a:b:c=6:15:20

=2:5:10

B. If x:y = 1:2 and y:z = 4:5,

x:y=x/y=1:2

y:z=y/z=4:5

x/y*y/z=x/z

1/2*4/5=x/z

4/10=x/z

2/5=x/z

Therefore, x:z=2:5

x:y:z

x:y=1:2

y:z=4:5

y is common to both ratio

Take the LCM of y values in both ratio

LCM of 2 and 4 =4

So,we will change the value of y in the first and second ratio to 4

By doing this, we will multiply the whole first ratio by 2

We have, 2:4

We will also multiply the whole second ratio by 1

We have, 4:5

Therefore, x:y:z=2:4:5

8 0
3 years ago
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