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sladkih [1.3K]
3 years ago
12

Andre builds a form for a new cement step in the shape of a rectangular prism. The form he builds is 40 and 1/2 inches long, 10

inches deep, and 8 inches high. How much cement is needed to fill the form?
Mathematics
1 answer:
posledela3 years ago
8 0

Answer:

3240 in^3

Step-by-step explanation:

Step one:

given data

The dimension of the form

Length 40 and 1/2 inches long,

Depth 10 inches deep,

The width and 8 inches high

Step two:

The amount of cement is equivalent to the volume of the form

V=L*W*H\\\\V=40.5*10*8\\\\V=3240 in^3

Hence the volume of cement is 3240 in^3

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Prove that for all integers a and b, if a mod 7 = 5 and b mod 7 = 6 then ab mod 7 = 2.
sergiy2304 [10]
Hello :
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6 0
3 years ago
Solve the system of equations y = 2x + 3 and 4x - 2y = -6 using a graphical method.
emmasim [6.3K]

Answer:

-1

Step-by-step explanation:

You are asked to solve this set by substitution. Note that the first equation defines

the value of y in terms of x. Therefore, you can use the right side of this equation

(2x + 3) as a substitution for y in the second equation. When you substitute 2x +3 for y

in the second equation, the result is:

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2x + 3 = 4x + 7

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Let's set the goal of getting all the terms that contain x isolated on the left side of

the equal sign and all the constants by themselves on the right side. Begin by getting rid

of the +3 on the left side by subtracting 3 from the left side. But if you subtract

3 from the left side you must also subtract 3 from the right side. These subtractions

result in the following sequence:

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2x + 3 - 3 = 4x + 7 - 3

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Combining numbers on the left side and on the right side simplifies the equation to:

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2x = 4x + 4

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Now, in a similar fashion, let's get rid of the 4x on the right side by subtracting

4x from the right side. When we do this subtraction, to keep the equation in balance

we must also subtract 4x from the left side. This results in:

.

 

2x - 4x = 4x - 4x + 4

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On both sides of the equation combine terms containing x to get:

.

-2x = 4

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Finally, solve for x by dividing both sides of the equation by -2 because -2 is the multiplier

of x. This results in:

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x = 4/-2 = -2

.

So now that we know x = -2, we can return to either one of the original equations  

in the equation set and substitute -2 for x. Then we can solve for y. Let's return

to the first equation and substitute -2 for x. This begins with:

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y = 2x + 3

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Then substituting -2 for x gives:

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y = 2*(-2) + 3 = -4 + 3 = -1

7 0
2 years ago
Hello I’m trying to solve this problem I just don’t know how to do it.
Katyanochek1 [597]

Step-by-step explanation:

To evaluate the proposed, the comprehension of linear data is required,

Slope: The rise/run or the accumulative unit distance between two differentiated points on a linear.

X-intercept: The peculiar point in which the observed linear data intersects the x-axis.

Y-intercept: The peculiar point in which the observed linear data intersects the y-axis.

1. To solve the following systems, first convert the Slope-Intercept formatting to Standard (General) form:

y = -5/3x + 3

3(Y = -5/3x + 3) Product by the denominator to eliminate the fraction.

3y = -5x + 9. Add 5x to the other expression as in standard form, the slope must be positive.

5x + 3y = 9 <== Standard (General) Form.

Y = 1/3x - 3

3(y = 1/3x - 3). Product by the denominator to eliminate the fraction.

3y = x - 9. Subtract by x to place the slope within the other expression of the equation.

-1(-x + 3y = -9). Now, product by -1 to contribute to a positive slope.

X - 3y = 9 <=== Standard (General) Form.

2. To solve for the x and y values, utilize the system of substitution:

1(5x + 3y = 9)Multiply equations by opposite slope to the other, and a positive to other.

-5(X - 3y = 9)

Evaluate,

+ 5x + 3y = 9. Now, add the systems.

-5x + 15y = -45

——————————

18y = -36

Y = -2

Thus, now that y is equated to -2, substitute that to either equation.

X - 3y = 9

X - 3(-2) = 9

X + 6 = 9

X = 3

Thus, x = 3, y = -2. This is their intersection point.

To plot these lines on the graph, execute the following,

Y = -5/3 x + 3

Start with the y-intercept. Draw a point on number 3 on the y-axis (vertical).

Starting with that point, go down 5 units, right 3 units.

* Remember, if there is a negative rise, go down. Positive, go up. If there is a negative run, go left. Positive, go right.

* Keep going 5 units down, right 3 units, until the graph allows.

2. Y = 1/3 x - 3

Similarly, conduct the same steps:

Starting with the y-intercept, draw a point on -3 on the vertical, or y-axis.

Beginning on that point, go up 1 unit, right 3 units.

Keep going up 1 units and 3 units right until the graph permits.

*I hope this helps.

3 0
2 years ago
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