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Ilya [14]
3 years ago
14

HELP THIS IS DUE TONIGHT AT 12!!!

Mathematics
2 answers:
strojnjashka [21]3 years ago
7 0
I know i’m late but... i hope this still helps. (-3,-10)
Kamila [148]3 years ago
3 0
The answer is (-3, -10)
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The value -2 is a lower bound for the zeros of the function shown below.
Juliette [100K]

Answer:

  a) true

Step-by-step explanation:

The bottom-line numbers from synthetic division <em>alternate signs</em>, indicating that -2 is a lower bound. The given statement is true.

__

If the signs were all positive, it would indicate the proposed zero is an <em>upper bound</em>.

__

A graph shows all real zeros are greater than -2.

4 0
4 years ago
Given that y varies directly with x in the table below, what is the value of y if the value of x is 7?
Black_prince [1.1K]
Write out the governing equation:

y = kx.

Take any point from the given table.  You haven't shared the table, so I will invent a point:  (2, 9).

Then find k:  k = 9/2        Then the equation becomes   y = (9/2)x.

Now let x = 7 and find y:                           y = (9/2)(7) = 63/2     

Answer:         y = 63/2
6 0
3 years ago
Read 2 more answers
6i-5=-17 what does i equal
vagabundo [1.1K]

Answer:

-2

Step-by-step explanation:

6i-5=-17

6i=-17+5

6i=-12

i=-12/6

i=-2

7 0
3 years ago
Read 2 more answers
Find the quotient 9 3/5 divided by 8/15
bazaltina [42]

Answer:

18

Step-by-step explanation:

4 0
3 years ago
Find the standard form of the equation for the circle with the following properties.
nataly862011 [7]

Answer:

(x+6)^2+(y+\frac{7}{6})^2=\frac{49}{36}

Step-by-step explanation:

So, we know that the center of the circle is at (-6, -7/6).

To find the equation of our circle that is tangent to the x-axis, we just need to find the vertical distance from our center to the x-axis.

Our center is at (-6, -7/6). The vertical distance from this to the x-axis directly above will be (-6, 0).

So, find our distance by subtracting our x-values:

d=r=0-(-7/6)

Subtract:

d=r=7/6

So, our distance, which is also our radius, will be 7/6.

Now, we can use the standard form for a circle, which is:

(x-h)^2+(y-k)^2=r^2

Where (h, k) is the center and r is the radius.

Substitute -6 for h, -7/6 for k, and 7/6 for r. This yields:

(x+6)^2+(y+\frac{7}{6})^2=\frac{49}{36}

We can confirm by graphing (using a calculator):

7 0
3 years ago
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