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zalisa [80]
3 years ago
14

Help as fast possible I’ll mark you bbrainlist

Chemistry
2 answers:
velikii [3]3 years ago
8 0
The gravitational pull is decreased as it gets farther from the sun and it has to go a farther distance.
olya-2409 [2.1K]3 years ago
5 0

Answer:

the farther they are the longer there cycle is. closer they are shorter time.

You might be interested in
He fuel used in many disposable lighters is liquid butane, c4h10c4h10. butane has a molecular weight of 58. 1 grams in one mole.
snow_lady [41]

Carbon atoms present in 2. 00 g of butane is 8.28 × 10^22.

Molecular weight of C4H10 is = 58.1 grams

Moles of butane = given mass/ molar mass

= 2/58.1

= 0.0344 mol

Multiply the number of moles by Avogadro's number. This will let you obtain the number of butane molecules:

0.0344 x 6.023 x 10^{23} molecules of butane = 2.07 × 10^22 molecules

of butane

Now multiply this number by four (due to four carbon atoms per butane molecule) to obtain the answer:

so, no. of carbon atoms = 4 x 2.07x 10^22 = 8.28x 10^22 atoms.

Thus the no. of carbon atom is 8.28×10^22.

learn more about butane or moles:

brainly.com/question/899549

#SPJ4

8 0
2 years ago
Lead(II) nitrate and ammonium iodide react to form lead(II) iodide and ammonium nitrate according to the reaction Pb ( NO 3 ) 2
nikklg [1K]

Answer : The volume of NH_4I solution required is, 2.93 L

The number of moles of PbI_2 formed from the reaction is, 0.662 moles.

Explanation :

First we have to calculate the initial moles of Pb(NO_3)_2.

\text{Moles of }Pb(NO_3)_2=\text{Concentration of }Pb(NO_3)_2\times \text{Volume of solution}

\text{Moles of }Pb(NO_3)_2=0.700M\times 0.945L=0.662mol

Now we have to calculate the moles of NH_4I

The balanced chemical reaction is:

Pb(NO_3)_2(aq)+2NH_4I(aq)\rightarrow PbI_2(s)+2NH_4NO_3(aq)

From the balanced chemical reaction we conclude that,

As, 1 mole of Pb(NO_3)_2 react with 2 moles of NH_4I

So, 0.662 mole of Pb(NO_3)_2 react with 0.662\times 2=1.32 moles of NH_4I

Now we have to calculate the volume of NH_4I

\text{Volume of }NH_4I=\frac{\text{Moles of }NH_4I}{\text{Concentration of }NH_4I}

\text{Volume of }NH_4I=\frac{1.32mol}{0.450mol/L}=2.93L

Now we have to calculate the moles of PbI_2

From the balanced chemical reaction we conclude that,

As, 1 mole of Pb(NO_3)_2 react to give 1 moles of PbI_2

So, 0.662 mole of Pb(NO_3)_2 react to give 0.662 moles of PbI_2

Thus, the number of moles of PbI_2 formed from the reaction is, 0.662 moles.

7 0
3 years ago
WHOEVER COMPLETES THIS GETS BRAINLIEST!!!!!!!!!<br> THANKS
Dmitry_Shevchenko [17]
That’s all i’ve gotten so far sorry

6 0
3 years ago
The reaction for the formation of phosgene from carbon monoxide and chlorineCO + Cl2 --&gt; COCl2 is first order in CO and secon
Ilya [14]

Answer:

r = k . [CO] .[Cl_{2}]

Explanation:

Let´s consider the following reaction:

CO + Cl₂ ⇒ COCl₂

The general rate law is:

r = k . [CO]^{m}. [Cl_{2}]^{n}

where,

r is the rate of the reaction

k is the rate constant

[CO] and [Cl₂] are the molar concentrations of each reactant

m and n are the reaction orders for each reactant

Since the reaction is first order in CO, m = 1. The overall order is the sum of all the individual orders. In this case, the overall order m + n = 2. Then,

m + n = 2

n = 2 - m = 2 - 1 = 1

The reaction is first order in Cl₂.

The rate law is:

r = k . [CO]. [Cl_{2}]

6 0
4 years ago
When 21.45 g of KNO3 was dissolved in water in a calorimeter, the temperature fell from 25.00°C to 14.14 °C. If the heat capacit
pashok25 [27]

25.9 kJ/mol. (3 sig. fig. as in the heat capacity.)

<h3>Explanation</h3>

The process:

\text{KNO}_3\;(s) \to \text{KNO}_3\;(aq).

How many moles of this process?

Relative atomic mass from a modern periodic table:

  • K: 39.098;
  • N: 14.007;
  • O: 15.999.

Molar mass of \text{KNO}_3:

M(\text{KNO}_3) = 39.098 + 14.007 + 3\times 15.999 = 101.102\;\text{g}\cdot\text{mol}^{-1}.

Number of moles of the process = Number of moles of \text{KNO}_3 dissolved:

\displaystyle n = \frac{m}{M} = \frac{21.45}{101.102} = 0.212162\;\text{mol}.

What's the enthalpy change of this process?

Q = C\cdot \Delta T = 0.505 \times (25.00 - 14.14) = 5.4843\;\text{kJ} for 0.212162\;\text{mol}. By convention, the enthalpy change \Delta H measures the energy change for each mole of a process.

\displaystyle \Delta H = \frac{Q}{n} = \frac{5.4843\text{kJ}}{0.212162\;\text{mol}} = 25.8\;\text{kJ}\cdot\text{mol}^{-1}.

The heat capacity is the least accurate number in these calculation. It comes with three significant figures. As a result, round the final result to three significant figures. However, make sure you keep at least one additional figure to minimize the risk of rounding errors during the calculation.

4 0
3 years ago
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