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stealth61 [152]
2 years ago
11

Use the information giving in the figure to find the length FH. If applicable, round your answer to the nearest whole number.

Mathematics
1 answer:
Dimas [21]2 years ago
5 0

9514 1404 393

Answer:

  FH = 16

Step-by-step explanation:

ΔGHE is a 5-12-13 triangle.

ΔEHF is a 3-4-5 triangle with a scale factor of 4, so side FH is 4·4 = 16 units.

_____

(3, 4, 5), (5, 12, 13), (7, 24, 25), (8, 15, 17) are all commonly used Pythagorean triples. The first two on the list are used in these triangles.

If you like, you can work out the numbers using the Pythagorean theorem, which tells you the square of the hypotenuse is equal to the sum of the squares of the other two sides.

For ΔEHG, that is ...

  GE² = EH² + HG²

  13² = EH² + 5²

  EH² = 13² -5² = 169 -25 = 144

And for ΔEHF, ...

  FE² = EH² +HF²

  20² = 144 + HF²

  400 -144 = HF² = 256

  HF = √256 = 16

The length of side FH is 16 units.

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kkurt [141]
The answer is 223.75 because you multiply 12.5 and 17.9
5 0
3 years ago
A.48<br> B.54<br> C.102<br> D.105
Mars2501 [29]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
8) Find the endpoint Cif M is the midpoint of segment CD and M (2, 4) and D (5,7)
Elenna [48]

Answer:

8. c. (-1, -1)

9. a. (-6, -1)

b. True

Step-by-step Explanation:

8. Given the midpoint M(2, 4), and one endpoint D(5, 7) of segment CD, the coordinate pair of the other endpoint C, can be calculated as follows:

let D(5, 7) = (x_2, y_2)

C(?, ?) = (x_1, y_1)

M(2, 4) = (\frac{x_1 + 5}{2}, \frac{y_1 + 7}{2})

Rewrite the equation to find the coordinates of C

2 = \frac{x_1 + 5}{2} and 4 = \frac{y_1 + 7}{2}

Solve for each:

2 = \frac{x_1 + 5}{2}

2*2 = \frac{x_1 + 5}{2}*2

4 = x_1 + 5

4 - 5 = x_1 + 5 - 5

-1 = x_1

x_1 = -1

4 = \frac{y_1 + 7}{2}

4*2 = \frac{y_1 + 7}{2}*2

8 = y_1 + 7

8 - 7 = y_1 + 7 - 7

1 = y_1

y_1 = 1

Coordinates of endpoint C is (-1, 1)

9. a.Given segment AB, with midpoint M(-4, -5), and endpoint A(-2, -9), find endpoint B as follows:

let A(-2, -9) = (x_2, y_2)

B(?, ?) = (x_1, y_1)

M(-4, -5) = (\frac{x_1 + (-2)}{2}, \frac{y_1 + (-9)}{2})

-4 = \frac{x_1 - 2}{2} and -5 = \frac{y_1 - 9}{2}

Solve for each:

-4 = \frac{x_1 - 2}{2}

-4*2 = \frac{x_1 - 2}{2}*2

-8 = x_1 - 2

-8 + 2 = x_1 - 2 + 2

-6 = x_1

x_1 = -6

-5 = \frac{y_1 - 9}{2}

-5*2 = \frac{y_1 - 9}{2}*2

-10 = y_1 - 9

-10 + 9 = y_1 - 9 + 9

-1 = y_1

y_1 = -1

Coordinates of endpoint B is (-6, -1)

b. The midpoint of a segment, is the middle of the segment. It divides the segment into two equal parts. The answer is TRUE.

4 0
3 years ago
Which of the following is equivalent to 8x2+20x+
kkurt [141]
<h2>answer </h2><h2>36</h2>

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7 0
3 years ago
Use set-builder notation to describe the following sets: (a) {1,2,3,4,5,6,7} (b) {1, 10, 100, 1000, 10000} (c) {1,1/2, 1/3, 1/4,
Alja [10]

Answer:

A) The set builder notation is: {n | n∈Z, 1≤n≤7}.

B) The set builder notation is: \{10^x | x=0,1,2,3,4\}

C) The set builder notation is: \{\frac{1}{n} | n\in z\}

D) The set builder notation can be: \{x\ \in R | x=x^3\ and\ x\neq 1\}

Step-by-step explanation:

Consider the provided information,

We need to use set-builder notation to describe the following sets.

(a) {1,2,3,4,5,6,7}

Here, the number are integer starting from 1 to 7.

Thus, the set builder notation is: {n | n∈Z, 1≤n≤7}.

(b) {1, 10, 100, 1000, 10000}

The above set can be written as:

\{1, 10, 100, 1000, 10000\}=\{10^0, 10^1, 10^2, 10^3, 10^4\}

Thus, the set builder notation is: \{10^x | x=0,1,2,3,4\}

(c) {1, 1/2, 1/3, 1/4, 1/5, ...}

Here the numerator is 1 for each term but denominator is natural number.

Thus, the set builder notation is: \{\frac{1}{n} | n\in z\}

(d) {0}

The set builder notation can be: \{x\ \in R | x=x^3\ and\ x\neq 1\}

8 0
3 years ago
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