Answer:
According to the Safety Data Sheet (SDS), the major harzard of concentrated HCl is that it may cause severe burns to skin, eyes and mucous membranes.
Explanation:
The SDS also informs that:
Most Important Hazards:
- May cause severe burns to skin, eyes and mucous membranes.
- Steam produced is irritating.
- Pollution of rivers and water bodies by changing the pH. Affects flora and fauna that comes in contact with acid.
Product Effects:
- If in direct contact with eyes will cause serious burns and vision loss.
Adverse effects to human health:
- Inhalation causes severe respiratory tract irritation. May cause pulmonary edema. The contact with the skin causes burns, which can lead to dermatitis. Prolonged contact of acid leads to visual damage to vision loss. If swallowed, may cause burns to the mucous membranes of the mouth and digestive system.
Environmental Effects:
- Affects rivers and streams by changing the pH of the water. May contaminate the soil. Vapors may temporarily affect air quality.
Physical and chemical hazards:
- Reacts with metals such as; iron, aluminum, zinc, magnesium, among others, forming hydrogen, which mixed with air may cause explosion and air displacement upon ignition under specific.
Answer:
Explanation:
NaNO₃ = Na⁺ + NO₃⁻¹
.497 M .497 M
moles of NO₃⁻¹ = .897 x .497 = .4458 moles
Ca( NO₃)₂ = Ca + 2 NO₃⁻¹
.341 M 2 x .341 M = .682 M
moles of NO₃⁻¹ = .813 x .682 = .5544 moles
Total moles = .4458 moles + .5544 moles
= 1.0002 moles
volume of solution = 897 + 813 = 1710 mL
= 1.710 L
concentration of nitrate ion = 1.0002 / 1.710 M
= .585 M
Answer:
At a given temperature, a system of particles can be considered as point masses (m) each moving at a certain translational velocity (v). The motion of these particles can be defined in terms of their average translational kinetic energy which is responsible for the heat transfer during molecular collisions and therefore the temperature of the system.
The kinetic temperature T is given in terms of the average translational kinetic energy as:
T = 2/3k(Kinetic energy)
T = 2/3k(1/2*m*v²)
where K = Boltzmann constant
Ans: C) Average translational kinetic energy