N2 + CaC2 = CaNCN + C
<span>As you can see, 1 mol of N2 can react completely with 1 mol of CaC2 and 1 mol of CaNCN will be obtained </span>
<span>It means 5 mol of N2 can react completely with 5 mol of CaC2 and 5 mol of CaNCN will be obtained </span>
<span>So, there are 7.5 - 5 = 2.5 odd mole of CaC2 after the reaction </span>
<span>And the mass of obtained CaNCN is </span>
<span>m = n*M = 5*80 = 400g</span>
18. have a nice day hope it helps.
Since temperature is held constant; Boyle's law can be expressed as: P 1 * V 1 = P 2 * V 2
Where P1 = 625 and V1 = 0.5 L
V2 = 925 * 10^(-3) = 0.925 L and P2 = ?
So P2 = (P1 * V1)/P2
P2 = (625 * 0.5)/0.925
P2 = 337.83 my hg
Ionic bond would form
e. g. NaCL
Answer:
Neutralization is when the pH (power of hydrogen ions) of a solution is at 7 (considered neutral in the pH scale). This means it's neither acidic nor basic and is neutral. In order to neutralize an acidic solution, you pour in the same amount of a strong base. And in order to neutralize a basic solution, you pour in the same amount of a strong base.
A neutralization reaction will give you salt and water. A common neutralization reaction could be:
HCl (strong acid) + NaOH (strong base) ----> NaCl (Salt) + H2O (water)
