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REY [17]
3 years ago
6

Which part of a cell synthesises proteins?

Chemistry
1 answer:
Yuki888 [10]3 years ago
8 0

Answer :

ribosome

Explanation:

Protein synthesis takes place in association with the ribosomes, which are small bodies found in the cytoplasm and particularly in the endoplasmic reticulum area.

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Is lithium ionization energy high low or medium?
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It’s soft which makes It low energy
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PLEASE ANSWER
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The answer is D) White Light!

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Consider four elements from Group 7A: fluorine in the second period, chlorine in the third period, bromine in the fourth period,
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Onization energy is the energy required to lose an electron and form an ion. The stronger is the attraction of the atom and the electron the higher the ionization energy, and the weaker is the attraction of the atom and the electron the higher the ionization energy. This leads to a clear trend in the periodic table. Given that the larger the atom the weaker the attraction of the atom to the valence electrons, the easier they will be released, and the lower the ionization energy. This is, as you go downward in a group, the ionization energy decreases. So, the element at the top of the group will exhibit the largest ionization energy. <span>Therefore, the answer is that of the four elements of group 7A, fluorine will have the largest first ionization energy.</span>
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List the following molecules in order of increasing boiling point: Br2, Cl2, F2, I2.
Andrej [43]

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1. None of these have hydrogen bonding.

2. None of these have dipoles.

3. Bigger molecules will have stronger London dispersion forces. So I2 has the strongest forces,

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Calculate the theoretical yield of alum expected from 0.9875 g of aluminum foil. assume the aluminum is the limiting reactant.
skelet666 [1.2K]

Answer: 17.34 grams of alum will be produced if 0.9875 g of Aluminium foil was used.

Explanation: Reaction to form alum from Aluminium is given as:

2Al(s)+2KOH(aq.)+2H_2O(l)+4H_2SO_4(aq.)\rightarrow 2KAl(SO_4)_2(s).12H_2O(l)+3H_2(g)

We are given Aluminium to be the limiting reactant, so the formation of alum will be dependent on Aluminium because it limits the formation of product.

By stoichiometry,

2 moles of Al is producing 2 moles of Alum

Mass of 2 moles of Aluminium = (2 × 27)g/mol = 54 g/mol

Mass of 2 moles of alum = (2 × 474)g/mol = 948 g/mol

54 g/mol of aluminium will produce 948 g/mol of alum, so

\text{0.9875 grams of aluminium will produce}=\frac{948g/mol}{54g/mol}\times 0.9875g

Amount of Alum produced = 17.34 grams

Theoretical yield of alum = 17.34 grams.

5 0
3 years ago
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