Answer:
Volume = 45.62L
Explanation:
Data;
V1 = 54.9L
T1 = 64°C = (64 + 273.15)k = 337.15K
T2 = 7°C = (7 + 273.15)k = 280.15K
V2 = ?
From Charles law,
The volume of a fixed mass of gas is directly proportional to its temperature provided that pressure remains constant
V = KT, K = V / T = V1 / T1 = V2 / T2 = V3 / T3 =.........= Vn / Tn
(54.9 / 337.15) = (V2 / 280.15)
V2 = (54.9 * 280.15) / 337.15
V2 = 45.618L
V2 = 45.62L
CrO as we need to find the empirical formula (simplest formula) not molecular formula
The reaction:
2 H 2 + O 2 → 2 H 2 O
2 Hydrogen molecules react with 1 Oxygen molecule to create 2 molecules of water.
We have to convert 53.8 g of Hydrogen into moles:
53.8 : 2.02 g / moles = 26.63 moles
2 moles H 2 ↔ 1 mole O 2
26.63 moles H 2 ↔ 13.32 moles O 2
Mass ( O 2 ) = 13.32 moles · 32 g/moles = 426.2 g
Answer: 426.2 grams of Oxygen.
Answer:
0.0251 M
Explanation:
We'll begin by writing the balanced equation for the reaction. This is given below:
HNO3 + KOH —> KNO3 + H2O
The mole ratio of the acid (nA) = 1
The mole ratio of the base (nB) = 1
Next, the data obtained from the question. This include the following:
Volume of acid (Va) = 10.1mL
Molarity of acid (Ma) =..?
Volume of base (Vb) = 61.9 mL
Molarity of base (Mb) = 0.0041 M
Next, we shall determine the molarity of the acid, HNO3 as follow:
MaVa/MbVb = nA/nB
Ma x 10.1 / 0.0041 x 61.9 = 1
Cross multiply to express in linear form
Ma x 10.1 = 0.0041 x 61.9
Divide both side by 10.1
Ma = (0.0041 x 61.9) /10.1
Ma = 0.0251 M
Therefore, the molarity of HNO3 is 0.0251 M
