Answer:
yep
Explanation:
that why I have someone else post questions for me. But its a good incentive to help others to help you to help me to you to help others.
Answer:
Q = 217.63J
Explanation:
Data;
Mass = 34.5g
T1 = 26.4°C
T2 = 75.3°C
c = 0.129J/g°C
Energy (Q) = mc(T2 - T1)
Q = 34.5 * 0.129 *(75.3 - 26.4)
Q = 4.4505 * 48.9
Q = 217.629J
Q = 217.63J
The heat gained was 217.63J
Answer:
0.95L
Explanation:
Data obtained from the question include:
V1 (initial volume) = 1L
T1 (initial temperature) = 315K
P1 (initial pressure) = 1.10 atm
T2 (final temperature) = stp = 273K
P2 (final pressure) = stp = 1atm
V2 (final volume) =?
Using the general gas equation P1V1/T1 = P2V2/T2, the final volume of the system can be obtained as follow:
P1V1/T1 = P2V2/T2
1.1 x 1/315 = 1 x V2/273
Cross multiply to express in linear form.
315 x V2 = 1.1 x 273
Divide both side by 315
V2 = (1.1 x 273) /315
V2 = 0.95L
Therefore, the final volume of the system if STP conditions are established is 0.95L
I believe it is the very first one
hope it helps :)
