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spin [16.1K]
2 years ago
7

WOULD YOU BE ABLE TO FORM RUST WITHOUT OXYGEN? Explain.

Chemistry
1 answer:
Aneli [31]2 years ago
4 0

Answer:

No

Explanation:

Rust is an iron oxide, a usually reddish-brown oxide formed by the reaction of iron and oxygen in the catalytic presence of water or air moisture.

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How do you prepare 1 liter of a 0.5 molar glucose solution?
riadik2000 [5.3K]
Answer: 90 grams

0.5 molar of glucose means 0.5mole glucose for 1 liter of water. Since we want to made 1L of solution, then the amount of glucose needed is: 0.5mole/l x 1l= = 0.5mole

Glucose molecular weight is 180, then 0,5 mol of glucose is= 0.5mole x 180 grams/mole= 90 grams.
6 0
3 years ago
ANSWER ASAP!!!! PLS HELP
tamaranim1 [39]

Answer: increase

Explanation: as pressure is increased, equlilibrium shifts towards the side with less moles of gas.  

6 0
1 year ago
Which of these scientist is know for his work in understanding climate change a : edwin hubble b : christian doppler c : warren
Airida [17]
I would say Edwin Hubble
8 0
3 years ago
Calculate the cell potential, the equilibrium constant, and the free energy change for
Tresset [83]

Answer:

Explanation:

Ba(s) + Mn²⁺ (aq,1M)  →      Ba²⁺ (aq,1M) + Mn(s)

Ba⁺²(aq) +2e →  Ba(s) ,  E° =  −2.90 V  

Mn⁺²(aq) +2e → Mn(s),  E⁰  =0.80 V

Anode reaction :

Ba(s)  →  Ba⁺²(aq) +2e        E° =  −2.90 V  

Cathode reaction :

Mn⁺²(aq) +2e → Mn(s)          E⁰  =0.80 V

Cell potential = Ecathode  - Eanode

Ecell  = .80 - ( - 2.90 )

Ecell = 3.7 V .

equilibrium constant ( K ) :

Ecell = .059 log K  / n

n = 2

3.7  = .059 log K  / 2

log K = 125.42

K = 2.63 x 10¹²⁵ .

Free energy change :

ΔG = - n F Ecell

= - 2 x 96500 x 3.7

= 714100 J

= 7.141 x 10⁵ J .

5 0
3 years ago
How many ml of 2.50 m hno3 are needed to prepare a 75.0 ml of 1.00 m hno3?
frez [133]
M1 * v1 = m2 * v2 
<span>2.50 * v1 = 1 * 75 
</span>2.50 * v1 = 75
2.50 * v1 /75= 75/75
<span>v1= 30 ml

The Answer is 30 ml</span>
3 0
3 years ago
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