The answers are true, true, false, true, and false.
Answer:
The correct answer is CaO > LiBr > KI.
Explanation:
Lattice energy is directly proportional to the charge and is inversely proportional to the size. The compound LiBr comprises Li+ and Br- ions, KI comprises K+ and I- ions, and CaO comprise Ca²⁺ and O²⁻ ions.
With the increase in the charge, there will be an increase in lattice energy. In the given case, the lattice energy of CaO will be the highest due to the presence of +2 and -2 ions. K⁺ ions are larger than Li⁺ ion, and I⁻ ions are larger than Br⁻ ion.
The distance between Li⁺ and Br⁻ ions in LiBr is less in comparison to the distance between K⁺ and I⁻ ions in KI. As a consequence, the lattice energy of LiBr is greater than KI. Therefore, CaO exhibits the largest lattice energy, while KI the smallest.
Answer:
25.1 g is the mass of chlorine in the sample
Explanation:
P . V = n . R . T
We apply the Ideal Gases Law to solve the excersise.
We need to convert the T°C to T°K → 37°C + 273 = 310K
We replace data: 3 atm . 3L = n . 0.082 L.atm /mol.K . 310K
9 atm.L / (0.082 L.atm /mol.K . 310K) = n → 0.354 moles
We convert the moles to mass, to reach the answer
0.345 mol . 70.9g / 1mol = 25.1 g
Answer:
0.071 mole
Explanation:
As discovered from Avogadro's hypothesis, 1 mole of any substance contains 6.02x10^23 molecules.
This simply means that 1 mole of H3PO4 also contains 6.02x10^23 molecules.
If 1 mole H3PO4 contains 6.02x10^23 molecules,
Then, xmol of H3PO4 will contain 4.3x10^22 molecules i.e
Xmol of H3PO4 = 4.3x10^22/6.02x10^23 = 0.071 mole
From the calculations made above, 4.3x10^22 molecules of H3PO4 have 0.071 mole of H3PO4
No it’s a very easy assignment
