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notsponge [240]
3 years ago
14

CH, + , 0, → _CO, + Н,0 Balance chemical equation

Chemistry
1 answer:
Flura [38]3 years ago
6 0

Answer:

2 CH2 + 3 O2 = 2 CO2 + 2 H2O

Explanation:

This is what I think that you meant by the question listed. When balancing a chemical equation, you want to make sure that there are equal amounts of each element on each side.

Originally, the equation's elements looked like this: 1 C on left & 1 C on right; 2 H on left & 2 H on right; 2 O on left and 3 O on right. Because these are not balanced, you need to add coefficients.

When adding coefficients, you need to make sure that all of the elements stay balanced, not just one that you are trying to fix. I know that some equations are really difficult to balance, and when that is the case, there are equation balancing websites that can help out.

However, what always helps me is making a chart and continuing to keep up with the changes I am making. It is a trial and error process.

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Please help me on this I’ll give 30 points
Rufina [12.5K]

Answer:

                     1. 10.66 moles of Al

                     2.  2.5 moles of Al₂O₃

                     3. 143.87 g of SO₂

Explanation:

                    The balance chemical equation is as follow,

                                      4 Al + 3 O₂ → 2 Al₂O₃

<h3>1.</h3>

According to balance chemical equation,

                       3 moles of O₂ required  =  4 moles of Al

So,

                     8 moles of O₂ will require  =  X moles of Al

Solving for X,

                      X =  8 mol × 4 mol / 3 mol

                      X =  10.66 moles of Al

<h3>2.</h3>

According to balance chemical equation,

                       4 moles of Al produced  =  2 moles of Al₂O₃

So,

                     5 moles of Al will produce  =  X moles of Al₂O₃

Solving for X,

                      X =  5 mol × 2 mol / 4 mol

                      X =  2.5 moles of Al₂O₃

<h3>3.</h3>

The balance chemical equation for the oxidation of carbon disulfide is as follow;

                                CS₂ + 3 O₂ → CO₂ + 2 SO₂

Step 1: <u>Calculate Moles of CS₂ as;</u>

                  Moles  =  Mass / M.Mass

                  Moles  =  85.5 g / 76.14 g/mol

                  Moles  =  1.12 moles of CS₂

Step 2: <u>Find out moles of SO₂ as;</u>

According to balance chemical equation,

                       1 mole of CS₂ produced  =  2 moles of SO₂

So,

                     1.12 moles of CS₂ will produce  =  X moles of SO₂

Solving for X,

                      X =  1.12 mol × 2 mol / 1 mol

                      X =  2.24 moles of SO₂

Step 3: <u>Calculate Mass of SO₂ as;</u>

                  Mass  =  Moles × M.Mass

                  Mass  =  2.24 mol × 64.06 g/mol

                  Mass  =  143.87 g of SO₂

4 0
3 years ago
Which question would be scientifically reasonable for a student to ask about the layers of the Earth?
lubasha [3.4K]

Answer:

The answer is C

Explanation:

5 0
3 years ago
During an experiment, the percent yield of calcium chloride from a reaction was 82.38%. Theoretically, the expected amount shoul
gregori [183]

Answer:

Actual yield = 86.5g

Explanation:

Percent yield = 82.38%

Theoretical yield = 105g

Actual yield = x

Equation of reaction,

CaCO₃ + HCl → CaCl₂ + CO₂ + H₂O

Percentage yield = (actual yield / theoretical yield) * 100

82.38% = actual yield / theoretical yield

82.38 / 100 = x / 105

Cross multiply and make x the subject of formula

X = (105 * 82.38) / 100

X = 86.499g

X = 86.5g

Actual yield of CaCl₂ is 86.5g

7 0
3 years ago
When concentrated sulfuric acid is poured onto sugar in a beaker and stirred, a vigorous exothermic reaction eventually occurs.
Vlada [557]
Missing question:
I. switching from granulated sugar to pow-dered sugar.
II. switching from powdered sugar to gran-ulated sugar.
III. warming up the sulfuric acid.
IV. putting the sulfuric acid container in an ice bath before use.
1. IV only
2. II only
3. III only
4. I and IV
5. I and III.
6. I only.
7. II and III
<span>8. II and IV.
Answer is: 5. </span>I and III.
If the surface area and temperature are increased, speed of reaction also increased<span>.</span>
7 0
3 years ago
The rate law for the decomposition of phosphine (PH3) is below. It takes 120. s for 1.00 M PH3 to decrease to 0.250 M. How much
Lubov Fominskaja [6]

Answer: 588.8 seconds

Explanation:

1.00 - 0.25 = 0.75M

4.00 - 0.320 = 3.68M

Therefore,

0.75M in 120 seconds

3.68M in x seconds

Cross multiply:

0.75*x = 120*3.68

x = 120*3.68/0.75

x = 588.8 seconds

8 0
4 years ago
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