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telo118 [61]
3 years ago
11

A solution is made by dissolving 3.8 moles of sodium chloride (NaCl) in 185 grams of water. If the molal boiling point constant

for water (Kb) is 0.51 °C/m, what would be the boiling point of this solution? Show all of the work needed to solve this problem.
Chemistry
1 answer:
IceJOKER [234]3 years ago
7 0
The boiling point of the solution can be calculated by the equation of the colligative property named boilng point elevation.

The formula for the boiling point elevation is:

ΔTb = i * Kb * m

Where:

i = van't Hoof factor
Kb = molal boiling point constant
m = molality.

Solution:

1) i is 2 because the NaCl is ionice and dissociates into two ions.

2) Kb is given = 0.51 °C/m

3) m = moles of solute / kg of solvent

moles of solute is given = 3.8

kg of solvent = 185 g * 1 kg/1000g = 0.185 kg

m = 3.8 moles / 0.185 kg = 20.54 m

4) ΔTb = 2 * 0.51°C/m * 20.54m = 20.9 °C

5) The boiling point is the normal boiling point of water (100°C) plus the increase:

Tb = 100°C + 20.9°C = 120.9°C

Answer: 120.9°C.

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3 0
3 years ago
An unknown compound was decomposed into 63.2 g carbon, 5.26 g hydrogen, and 41.6 g oxygen. what is its empirical formula?
ira [324]
Step 1:
           Divide mass of each element with its M.mass in order to find out moles.

                       C  =  63.2 g / 12 g/mol  =  Moles  =  5.26 moles

                       H  =  5.26 g / 1.008 g/mol  =  Moles  =  5.21 moles

                       C  =  41.6 g / 16 g/mol  =  Moles  =  2.6 moles

Step 2:
          Select moles of the element with least value and divide all moles of element by it,
                             C                H             O          
                       5.26/2.6  :  5.21/2.6  :  2.6/2.6

                          2.02     :     2.00     :       1

Result:
               Empirical Formula  =     C₂H₂O
4 0
4 years ago
Which gas law describes the relationship between volume and pressure at a constant temperature?
olasank [31]
Boyle law is a gas law stating the pressure and the volume of a gas have an inverse relationship when held at constant temperature.

5 0
3 years ago
A scientist measures the standard enthalpy change for the following reaction to be -327.2 kJ : P4O10(s) 6 H2O(l)4H3PO4(aq) Based
OleMash [197]

Answer:

ΔH°f P4O10(s) = - 3115.795 KJ/mol

Explanation:

  • P4O10(s) + 6H2O(l) ↔ 4H3PO4(aq)
  • ΔH°rxn = ∑νiΔH°fi

∴ ΔH°rxn = - 327.2 KJ

∴ ΔH°f H2O(l) = - 285.84 KJ/mol

∴ ΔH°F H3PO4(aq) = - 1289.5088 KJ/mol

⇒ ΔH°rxn = (4)(- 1289.5088) - (6)(- 285.84) - ΔH°f P4O10(s) = - 327.2 KJ

⇒ ΔH°f P4O10(s) = - 5158.035 + 1715.04 + 327.2

⇒ ΔH°f P4O10(s) = - 3115.795 KJ/mol

5 0
4 years ago
What is the pressure in atmospheres exerted by a 0.500 mole sample of nitrogen gas in a 10.0 L
Nonamiya [84]

Answer:

The pressure is 1, 22 atm.

Explanation:

We use deal gas formula. First, we convert the unit of temperature in Celsius into Kelvin. We use the constant R= 0,082 l atm /K mol.Then, we solve P (pressure).

0°C=273 K   25°C= 273 + 25= 298 K

PV=nRT   -----> P= (nRT)/V

P= (0,5 mol x 0,082 l atm /K mol x 298 K)/ 10 L

<em>P= 1, 2218 atm</em>

3 0
3 years ago
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