<span>They are the weakest of the intermolecular forces.
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<span>The atoms in a compound are held together by a chemical bond. The chemical bonds can be either covalent bonds or ionic bonds. Both the bonds are considered very strong bonds. These bonds are mainly formed by sharing of electrons or in the case when one of the elements making the compound donates electron to the other element. The nucleus of each atom attracts to form a strong bond. This property of attraction between the nucleus of the atoms actually helps in forming the chemical bonds.<span>
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Phosphoenol pyruvate enzyme is not part of gluconeogenesis.
<h3>Phosphoenol pyruvate</h3>
The ester formed when pyruvate and phosphate are combined to form an enol results in phosphoenol pyruvate (2-phosphoenolpyruvate, or PEP). As an anion, it exists. In biochemistry, PEP is a crucial intermediary. Involved in glycolysis and gluconeogenesis, it boasts the highest-energy phosphate bond yet discovered in an organism (61.9 kJ/mol). It also plays a role in carbon fixation and the manufacture of a number of aromatic chemicals in plants. In bacteria, it provides energy for the phosphotransferase system. Enolase reacts with 2-phosphoglyceric acid to produce PEP as a result. Pyruvate kinase (PK) converts PEP to pyruvic acid, and this process produces adenosine triphosphate (ATP) via substrate-level phosphorylation. One of the main units of currency for chemical energy in cells is ATP.
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To solve this we need to have knowledge of differential rate law which relate the rate to the concentration and time. Therefore, the rate of overall reaction is 1x10⁻²M/s.
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What is differential rate law? </h3>
A differential rate law represents the rate of a reaction . According to this rate is directly proportional to changes in the concentration of reactants and inversely proportional to specific interval of time. There is another expression of rate law which is integrated rate law which is just opposite of differential rate law.
The given equation is
2NO + O 2NO
(1/2) Rate of disappearance of NO= rate of disappearance of C= (1/2)rate of appearance of NO= rate of overall reaction.
(1/2)rate of appearance of NO= rate of overall reaction.
rate of appearance of NO=2x10⁻²M/s.
Substituting the values in above equation
(1/2)×2x10⁻²M/s = rate of overall reaction.
rate of overall reaction= 1x10⁻²M/s
Therefore, the rate of overall reaction is 1x10⁻²M/s.
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Answer:
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Explanation: