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UNO [17]
3 years ago
7

Compared to compounds that possess only dipole-dipole intermolecular forces, compounds that possess hydrogen bonding generally:

Chemistry
2 answers:
jeka57 [31]3 years ago
7 0

Answer:

Have higher melting points

Explanation:

Dipole-dipole forces and hydrogen bonds are intermolecular forces which are interactions that keep molecules together and are electrostatic forces.

Dipole-dipole forces are attraction’s forces between polar molecules because these molecules attract each other when the positive end of one is near the negative end of the other.

The hydrogen bonds are a type of dipole-dipole forces but in these interactions, we have a molecule that has in its structure hydrogen and another atom with high electronegativity, like oxygen, Fluor, nitrogen and sulfur. Due to the high electronegativity difference between these atoms these forces are stronger, so more energy is needed to put the molecules apart, hence the melting and boiling points of compounds that possess this interactios are higher.

Anna35 [415]3 years ago
4 0
I think the correct answer from the choices listed above is the first option. Compared to compounds that possess only dipole-dipole intermolecular forces, compounds that possess hydrogen bonding generally have <span>higher melting points. This is because hydrogen bonding is a stronger force than dipole-dipole.</span>
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6 0
3 years ago
Which element has 7 valence electrons
Olegator [25]

Answer:

Halogens have 7 valence electrons.

Explanation:

They are the most active non-metals including fluorine, chlorine, bromine, iodine, and astatine

3 0
3 years ago
A cylinder with a moveable piston contains 92g of Nitrogen. The external pressure is constant at 1.00 atm. The initial temperatu
Jobisdone [24]

Answer:

Work done in this process = 4053 J

Explanation:

Mass of the gas = 0.092 kg

Pressure is constant = 1 atm = 101325 pa

Initial temperature T_{1} = 200 K

Final temperature T_{2} = 200 - 85 = 115 K

Gas constant for nitrogen = 297 \frac{J}{kg k}

When pressure of a gas is constant, volume of the gas is directly proportional to its temperature.

⇒ V ∝ T

⇒ \frac{V_{2} }{V_{1} } = \frac{T_{2} }{T_{1} } ------------ ( 1 )

From ideal gas equation P_{1} V_{1} = m R T_{1} ------ (2)

⇒ 101325 × V_{1} = 0.092 × 297 × 200

⇒ V_{1} = 0.054 m^{3}

This is the volume at initial condition.

From equation 1

⇒ \frac{V_{2} }{0.054} = \frac{200}{115}

⇒ V_{2} = 0.094 m^{3}

This is the volume at final condition.

Thus the work done is given by W = P [V_{2} - V_{1} ]

⇒ W = 101325 × [ 0.094 - 0.054]

⇒ W = 4053 J

This is the work done in that process.

7 0
3 years ago
I need help with my homework.Calculate the number of formula units in: 41.5 grams CaBr2
lana66690 [7]

Answer:

\text{ }1.25\times10^{23}\text{ formula units}

Explanation:

Here, we want to calculate the number of formula units in the given molecule

We start by getting the number of moles

To get the number of moles, we have to divide the mass given by the molar mass

The molar mass is the mass per mole

The molar mass of calcium bromide is 200 g/mol

Thus, we have the number of moles as follows:

\frac{41.5}{200}\text{ = 0.2075 mol}

The number of formula units in a mole is:

1\text{ mole = 6.02 }\times10^{22}\text{ formula units}

The number of formula units in 0.2075 mole will be:

0.2075\text{ }\times6.02\times10^{23}\text{ = }1.25\times10^{23}\text{ formula units}

5 0
1 year ago
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Hoochie [10]
The correct answer is D . Milk
6 0
3 years ago
Read 2 more answers
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