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riadik2000 [5.3K]
3 years ago
12

How is a scale model different from other types of models?

Engineering
1 answer:
SVETLANKA909090 [29]3 years ago
6 0

Answer:

a scale model each size is a certain amount smaller

Explanation:

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People who pursue a career in the creative imaging fields have qualities like a good imagination, creativity, open minds,  good with ideas, and handling situations. If you enter that field, you need imagination to create things and an open mind to be open to all creations. You need good ideas to make good thing that will work.

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Which of the following is NOT one of the 3 technology bets we have made?
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The one that is not an option of the 3 technology bets made are  Digital core and Design Thinking.

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2 years ago
A rigid tank contains an ideal gas at 40°C that is being stirred by a paddle wheel. The paddle wheel does 240 kJ of work on the
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To solve the problem it is necessary to consider the concepts and formulas related to the change of ideal gas entropy.

By definition the entropy change would be defined as

\Delta S = C_p ln(\frac{T_2}{T_1})-Rln(\frac{P_2}{P_1})

Using the Boyle equation we have

\Delta S = C_p ln(\frac{T_2}{T_1})-Rln(\frac{v_1T_2}{v_2T_1})

Where,

C_p = Specific heat at constant pressure

T_1= Initial temperature of gas

T_2= Final temprature of gas

R = Universal gas constant

v_1= Initial specific Volume of gas

v_2= Final specific volume of gas

According to the statement, it is an isothermal process and the tank is therefore rigid

T_1 = T_2, v_2=v_1

The equation would turn out as

\Delta S = C_p ln1-ln1

<em>Therefore the entropy change of the ideal gas is 0</em>

Into the surroundings we have that

\Delta S = \frac{Q}{T}

Where,

Q = Heat Exchange

T = Temperature in the surrounding

Replacing with our values we have that

\Delta S = \frac{230kJ}{(30+273)K}

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