Absolute positions — latitudes and longitudes
Relative positions — azimuths, bearings, and elevation angles
Spherical distances between point locations
Answer:
10.984mm
Explanation:
by elastic modulus
stress=modulus of elasticity*strain
stress=loading/area area" cross-section"
11mm=0.011m
area=π(d/2)^2=π(0.011/2)^2=9.503*10^-5 square meter
stress=55000/(9.503*10^-5)=578.745 MPa
convert MPa and GPa to pascal.
strain=stress/modulus=(578.745*10^6)/(125*10^9)=0.00463............axial strain
v=Poisson ratio
lateral strain=(-v)*axial strain= -0.31*0.00463
lateral strain= -1.4353*10^-3=change in diameter/ original diameter
change in diameter=(-1.4353*10^-3)*0.011= -1.57883*10^-5 m
negative indicates decrease in diameter.
decrease in dia.=0.01578mm
new diameter=11-0.01578= 10.984mm
18.14% of the bags contains less than 22 kg
<h3>What is
z score?</h3>
Z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by:
z = (raw score - mean) / standard deviation
Given that:
Mean = 22.73 kg, standard deviation = 0.80 kg
a) For <22:
z = (22 - 22.73)/0.8 = -0.91
P(z < -0.91) = 0.1814
18.14% of the bags contains less than 22 kg
Find out more on z score at: brainly.com/question/25638875
Answer:
A) 2P/(¶r^2)
B) p/(¶r^2)
Explanation:
Force = P
Radius = r
Area on which force acts = ¶r^2
If both forces are applied, total stress will be
S = 2P/(¶r^2)
When only one of the force is applied
S = p/(¶r^2)