A2A.
Let the magnitude of the two forces be x and y.
Let resultant at right angle be p(= √15N) and at 60 degrees be q(= √18N.
Now, p = √(x2 + y2) = √15,
q = √(x2 + y2 +2xycos60) = √18.
So x2 + y2 = 15,
x2 + y2 + xy = 18,
therefore xy = 3 or y = 3/x.
Now, x2 + (3/x)2 = 15,
x4 + 9 = 15x2,
x4 - 15x2 + 9 = 0.
Now find the roots of this quadratic equation, the two values of x will correspond to the magnitudes of the two vectors.
Answer:
Option C: water pressure.
Explanation:
Water pressure allows water to reach the top of a building.
Answer:
Explanation:
a )
75°F = (75 - 32 ) x 5 / 9 = 35°C
35 + 273 = 308 K
75⁰F = 459.67 + 75 = 534.67° R
b )
F = C
5F - 160 = 9F
-4F = 160
F = - 40
Rankin = - 40 + 459.67 = 419.67
kelvin = -40 + 273 = 233K
c )
F = 2C
10 C - 160 = 9C
C = 160°C
F = 320°F
R = 320 + 459.67 = 779.67°R
K = 273 + 160 = 433 K .