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goldfiish [28.3K]
3 years ago
8

Which of the following statements do not correctly describe pull manufacturing? (1). Material flow is determined by the need of

the downstream workstation (2). Control is transferred from the beginning of the line to the end (3). A single piece flow is ideal for a push system and not for a pull system (4). Tries to minimize the number of items pulled at the same time Select one: a. (3) b. (1) and (3) c. (2) and (4) d. (4)
Engineering
1 answer:
weeeeeb [17]3 years ago
5 0

Answer: option B.(1) and (3)

(1). Material flow is determined by the need of the downstream workstation

(3). A single piece flow is ideal for a push system and not for a pull system

Explanation:

A pull system is a Lean manufacturing principle created to reduce waste in the production process. A pull system is to build products based on actual demand and not on forecasts.

One of the most important principles in the Lean Philosophy is the Pull Principle. The Pull principle is based on the assumption that one should only produce what is asked for by the customer. The Pull principle can be applied in more than just production, it can be applied in the office and even in life.

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The answer is the third statement- Tundra, wetland, rainforest, desert
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In a river reach, the rate of inflow at any time is 350 cfs and the rate of outflow is 285 cfs. After 90 min, the inflow and out
Semenov [28]

Answer:

change in storage =  -310,500 ft^3

intital storage= 3.67 acre ft

Explanation:

Given data:

Rate of inflow = 350 cfs

Rate of outflow = 285 cfs

After 90 min,  rate of inflow = 250 cfs

Rate of outflow = 200 cfs

final storage = 10.8 acre-ft

calculating the average inflow and outflow

average inflow  = \frac{(350+250)}{2} = 300 cfs

average outlow  = \frac{(285+200)}{2} = 242.5 cfs

total amount of water drain during the period of one hour

= (average outflow - average inflow) *60*90

= (242.5 - 300)*60*90 = -310,500

change in storage is calculate as

= -310,500 ft^3

in cubic meter

= -310500/35.315 = 8792.30 cm^3

in acre-ft

= -310,500/43560 = 7.13 acre ft

initial storage = 10.8 - 7.13 = 3.67 acre ft

3 0
3 years ago
Evaluate each of the following to three significant figures and express each answer in SI units using an appropriate prefix: (a)
Sonbull [250]

Answer:

Explanation:

(a)

\frac{354 mg \, 45 km}{0.0356 kN} = 354 mg \times \frac{1 kg}{10^6 mg} \times 45 km \times \frac{10^3m}{1 km} \times \frac{1}{0.0356 kN} \times \frac{1 kN}{10^3 N} = 0.447 \frac{kg \, m}{N}

(b)

0.00453 Mg \times 201 ms = 0.00453 Mg \times \frac{10^3 kg}{1 Mg} \times 201 ms \times \frac{1 s}{10^3 ms} = 0.911 kg \, s

(c)

\frac{435 MN}{23.2 mm} = 435 MN \times \frac{10^6 N}{1 MN} \times \frac{1}{23.2 mm}  \times \frac{10^3 mm}{1 m} = 18.75 \times 10^9 \frac{N}{m} = 18.75 \frac{GN}{m}

7 0
4 years ago
Your driver license will be _____ if you race another driver on a public road, commit a felony using a motor vehicle, or are fou
ser-zykov [4K]

Answer:

Revoked

Explanation:

Your driver license will be revoked if you race another driver on a public road, commit a felony using a motor vehicle, or are found guilty of reckless driving three times in one year.

4 0
2 years ago
A bar of 75 mm diameter is reduced to 73mm by a cutting tool while cutting orthogonally. If the mean length of the cut chip is 7
barxatty [35]

Answer:

r=0.31

Ф=18.03°

Explanation:

Given that

Diameter of bar before cutting = 75 mm

Diameter of bar after cutting = 73 mm

Mean diameter of bar d= (75+73)/2=74 mm

Mean length of uncut chip = πd

Mean length of uncut chip = π x 74 =232.45 mm

So cutting ratio r

Cutting\ ratio=\dfrac{Mean\ length\ of cut\ chip}{Mean\ length\ of uncut\ chip}

r=\dfrac{73.5}{232.45}

  r=0.31

So the cutting ratio is 0.31.

As we know that shear angle given as

tan\phi =\dfrac{rcos\alpha }{1-rsin\alpha }

Now by putting the values

tan\phi =\dfrac{rcos\alpha }{1-rsin\alpha }

tan\phi =\dfrac{0.31cos15 }{1-0.31sin15 }\

  Ф=18.03°

So the shear angle is 18.03°.

4 0
4 years ago
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