Hello,12(12)=144 True or false?

Mathematics

2 answers:

sweet [91]3 years ago

5 0

Answer: True

Explanation: 12 times 12 is 144

Gennadij [26K]3 years ago

4 0

Answer:

true................

Step-by-step explanation:

true

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Hello brainly please help me with this

Sedaia [141]

Answer:

Step-by-step explanation:

By multiplying 1/3 4 times, you would get 1/81 because you are multiplying the numerators by the numerators and the denominators by the denominators. However Priya is adding the fractions instead which gave her 4/3

I hope this helped xd

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3 years ago

Read 2 more answers

Help solve these algebraic fractions please with explanation would be great <3

sineoko [7]

Answer:

7/ Ans;

$\frac{x + 2}{ x + 4} \div \frac{ {x }^{2} - 2x - 8}{ {x}^{2} + 2x - 8} \\ \\ \\ \frac{x + 2}{x + 4} \times \frac{ {x}^{2} + 2x - 8 }{ {x}^{2} - 2x - 8} \\ \\ \\ \frac{x + 2}{x + 4} \times \frac{(x - 2)(x + 4)}{(x - 4)(x + 2)} \\ \\ \\ =1 \times \frac{x - 2}{x - 4} \\ \\ \\ = \frac{x - 2}{x - 4}$

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9/Ans;

$\frac{ {x}^{2} - 9}{ {x}^{2} - 6x + 9} \div \frac{x + 4}{x - 3} \\ \\ \frac{ {x}^{2} - 9 }{ {x}^{2} - 6x + 9} \times \frac{x - 3}{x + 4} \\ \\ \\ \frac{(x + 3)(x - 3)}{(x - 3)(x - 3)} \times \frac{x - 3}{x + 4} \\ \\ \\ = \frac{(x + 3)}{1} \times \frac{1}{(x + 4)} \\ \\ \\ = \frac{x + 3}{x + 4}$

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In the two questions, we first replace the division with multiplication with flipping the fraction after the division sign, secondly we analyze any equation that needs analysis to simplify it, thirdly, to simplify the fraction by deleting the numerator and the similar denominator .

5 0

2 years ago

Solve for x -

weqwewe [10]

$QUADRATIC \: \: RESOLUTIONS \\ \\ \\ Given \: \:expression - \\ \\ \frac{1}{a} + \frac{1}{b} + \frac{1}{c} = \frac{1}{a + b + x} \\ \\ \frac{1}{a} + \frac{1}{b} = \frac{1}{a + b + x} - \frac{1}{x} \\ \\ \frac{a + b}{ab} = \frac{ - (a + b)}{x(a + b + x)} \\ \\ \frac{1}{ab} = \frac{ - 1}{x(a + b + x)} \\ \\ Simplifying \: \: above \: \: expression \: \: , \: \\ \\ We \: get \: a \: Quadratic \: equation \: - \\ \\ {x}^{2} + (a + b)x + ab = 0 \\ \\ (x + a)(x + b) = 0 \\ \\ \\ || \: \: \: x = - a \: \: \: || \: \: \: x = - b \: \: \: || \: \: \: \: \: \: \: \: \: \: \: Ans.$