Answer:
the charged particle is electron..
Explanation:
electrons are the only charged particles which can be transferred by rubbing certain materials which generate electrostatic force ...
The physical evidence are the silent witnesses against the perpetrators of a crime
The correct option of what the field inspector packages after the crime scene has been photographed is the option;
Reason:
Physical evidence are evidence that originate from inanimate objects or origin that is nonliving, and includes every material or object that serve as an indicator that someone has committed a crime, or that can link a perpetrator to crime
Examples include; Documents, hair, skin, fingerprints, weapons, soil, or fibers
The field inspector, collects the evidence that shows that a crime has been committed which are the physical evidence, after the crime scene has been photographed
Therefore, the correct option is; <u>Physical evidence</u>
Learn more here:
brainly.com/question/16340616
Characteristics help us to classify seeds because different plants have different features.
<h3>How are characteristics used to identify and classify plants?</h3>
The divisions classify plants that are based on whether they reproduce by spores or seeds. Spore-bearing plants include ferns, club mosses, and horsetail while on the other hand, Seed-bearing plants are divided into gymnosperms and angiosperms. Different plants have different characteristics and features so on the basis of these characteristics we can easily classify seeds whether they belong from angiosperm and gymnosperm.
So we can conclude that characteristics help us to classify seeds because different plants have different features.
Learn more about seeds here: brainly.com/question/18799172
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<span>B.Extrinsic motivation </span>
Answer:
v = 8.09 m/s
Explanation:
For this exercise we use that the work done by the friction force plus the potential energy equals the change in the body's energy.
Let's calculate the energy
starting point. Higher
Em₀ = U = m gh
final point. To go down the slope
Em_f = K = ½ m v²
The work of the friction force is
W = fr L cos 180
to find the friction force let's use Newton's second law
Axis y
N - W_y = 0
N = W_y
X axis
Wₓ - fr = ma
let's use trigonometry
sin θ = y / L
sin θ = 11/110 = 0.1
θ = sin⁻¹ 0.1
θ = 5.74º
sin 5.74 = Wₓ / W
cos 5.74 = W_y / W
Wₓ = W sin 5.74
W_y = W cos 5.74
the formula for the friction force is
fr = μ N
fr = μ W cos θ
Work is friction force is
W_fr = - μ W L cos θ
Let's use the relationship of work with energy
W + ΔU = ΔK
-μ mg L cos 5.74 + (mgh - 0) = 0 - ½ m v²
v² = - 2 μ g L cos 5.74 +2 (gh)
v² = 2gh - 2 μ gL cos 5.74
let's calculate
v² = 2 9.8 11 - 2 0.07 9.8 110 cos 5.74
v² = 215.6 -150.16
v = √65.44
v = 8.09 m/s
