To find the change in centripetal acceleration, you should first look for the centripetal acceleration at the top of the hill and at the bottom of the hill.
The formula for centripetal acceleration is:
Centripetal Acceleration = v squared divided by r
where:
v = velocity, m/s
r= radium, m
assuming the velocity does not change:
at the top of the hill:
centripetal acceleration = (4.5 m/s^2) divided by 0.25 m
= 81 m/s^2
at the bottom of the hill:
centripetal acceleration = (4.5 m/s^2) divided by 1.25 m
= 16.2 m/s^2
to find the change in centripetal acceleration, take the difference of the two.
change in centripetal acceleration = centripetal acceleration at the top of the hill - centripetal acceleration at the bottom of the hill
= 81 m/s^2 - 16.2 m/s^2
= 64.8 m/s^2 or 65 m/s^2
Answer:
M = 0.730*m
V = 0.663*v
Explanation:
Data Given:
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Conservation of Momentum:
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Energy Balance:

Substitute Eq 2 into Eq 1
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Using Eq 1
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<span>When you are setting up your budget, it is easier to start by setting your budgeting amounts based on the average of your last three months of spending. Many budgeting programs can import past transactions and help you come up with the estimates that you need for your budget. Then you can begin to make adjustments after you have those initial amounts.
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The two main goals are to spend less than you earn and to know where your money is going. Once you have a working budget you can work towards your other goals of saving money and getting out of debt. It is important to avoid theses common budgeting mistakes <span>when setting up your budget.
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Answer:
The magnetic field is strongest at the center and weakest between the two poles just outside the bar magnet. The magnetic field lines are densest at the center and least dense between the two poles just outside the bar magnet.
Explanation: