You kick a ball with a speed of 14 m/s at an angle of 51°. How far away does the ball land?
2 answers:
Answer:
19.6 m
Explanation:
Apex ; good luck to all :)
-- The vertical component of the ball's velocity is 14 sin(<span>51°) = 10.88 m/s -- The acceleration of gravity is 9.8 m/s². -- The ball rises for 10.88/9.8 seconds, then stops rising, and drops for the same amount of time before it hits the ground. -- Altogether, the ball is in the air for (2 x 10.88)/(9.8) = 2.22 seconds ================================== -- The horizontal component of the ball's velocity is 14 cos(</span><span>51°) = 8.81 m/s -- At this speed, it covers a horizontal distance of (8.81) x (2.22) = <em><u>19.56 meters</u></em> before it hits the ground. As usual when we're discussing this stuff, we completely ignore air resistance. </span>
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