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AnnyKZ [126]
3 years ago
5

a ball of mass 0.5 kg is released from rest at a height of 30 m. how fast is it going when it hits the ground? acceleration due

to gravity is g = 9.8 m/s^2
Physics
1 answer:
Vera_Pavlovna [14]3 years ago
8 0

Answer:

24.25m/s

Explanation:

m = 0.5kg

u ( initial velocity) = 0m/s

v ( final velocity) =?

a = 9.8m/s^2

d (displacement) = 30m

Since u don't have time, u only have the choice to use this formula

V^2 = u^2 + 2ad

V^2 = 0 + 2 x 9.8 x 30

V^2 = 588

V = 24.25 m/s

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Pleae answer asap brcianset
marshall27 [118]

Answer:

>

Explanation:

1/8 is greater than 3/20

5 0
2 years ago
I need some help w/ this:
pochemuha

Answer:

The velocity of the police car is, v = 17.798 m/s

Explanation:

Given data,

The actual frequency of the siren, f = 2010 Hz

The observed frequency of siren is, f' = 2120 Hz

The velocity of the observer, v' = 0 m/s

The velocity of the source, v = ?

The formula for Doppler effect,

                            f'=\frac{(V+v')}{(V-v)}f

Where,

                         V - velocity of sound waves in air.

                          v=V-(V+v')\frac{f}{f'}

Substituting the given values,

                         v=343-(343+0)\frac{2010}{2120}

                                 v = 17.798 m/s

Hence, the velocity of the police car is, v = 17.798 m/s

5 0
2 years ago
A car and a lorry are about to collide. When they collide the two vehicles become tightly locked together. The lorry is going at
BartSMP [9]

Answer:

The speed of the vehicles immediately after the collision is 5.84 m/s.

Explanation:

The speed of the vehicles after the collision can be found by conservation of linear momentum:

p_{i} = p_{f}

m_{1}v_{1_{i}} + m_{2}v_{2_{i}} = m_{1}v_{1_{f}} + m_{2}v_{2_{f}}

Where:

m₁: is the mass of the car = 0.5 ton = 500 kg

m₂: is the mass of the lorry = 9.5 ton = 9500 kg

v_{1_{i}}: is the initial speed of the car = 40 km/h = 11.11 m/s

v_{2_{i}}: is the initial speed of the lorry = 20 km/h = 5.56 m/s

v_{1_{f}}: is the final speed of the car =?

v_{2_{f}}: is the final speed of the lorry =?    

Since the two vehicles become tightly locked together after the collision v_{1_{f}} = v_{2_{f}}:

m_{1}v_{1_{i}} + m_{2}v_{2_{i}} = v(m_{1} + m_{2})

v = \frac{m_{1}v_{1_{i}} + m_{2}v_{2_{i}}}{m_{1} + m_{2}} = \frac{500 kg*11.11 m/s + 9500 kg*5.56 m/s}{500 kg + 9500 kg} = 5.84 m/s

Therefore, the speed of the vehicles immediately after the collision is 5.84 m/s.

I hope it helps you!  

8 0
2 years ago
The steering wheel of a car has a radius of 0.19 m, and the steering wheel of a truck has a radius of 0.25 m. The same force is
kodGreya [7K]

Answer:

\frac{T_t}{T_c} = 1.32

Explanation:

The torque applied on an object can be calculated by the following formula:

T = Fr

where,

T = Torque

F = Applied Force

r = radius of the wheel

For car wheel:

T_c = Fr_c\\

For truck wheel:

T_t = Fr_t

Dividing both:

\frac{T_t}{T_c} = \frac{Fr_t}{Fr_c}

for the same force applied on both wheels:

\frac{T_t}{T_c} = \frac{r_t}{r_c} \\

where,

rt = radius of the truck steering wheel = 0.25 m

rc = radius of the car steering wheel = 0.19 m

Therefore,

\frac{T_t}{T_c} = \frac{0.25\ m}{0.19\ m} \\

\frac{T_t}{T_c} = 1.32

8 0
3 years ago
Why can't I get a new phone
Alenkasestr [34]

Answer:

Idk I think we all ask the question also this question is for sure prob getting deleted just saying now not by me

Explanation:

3 0
2 years ago
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