Answer:
The distance on the screen from the center of the central bright fringe to the third dark fringe is 0.831 m.
Explanation:
Given that,
Wavelength = 617 nm
Width of slit
Distance between the slit and screen L= 2.83 m
Third dark fringe m = 3
We need to calculate the distance on the screen from the center of the central bright fringe to the third dark fringe on either side
Using formula of distance
Put the value into the formula
Hence, The distance on the screen from the center of the central bright fringe to the third dark fringe is 0.831 m.
A: 132.9w because 2525\19 is how much energy transferred per second which is also known as the power
Answer:
g' = 13.5 m/s²
Explanation:
The acceleration due to gravity on surface of earth is given by the formula:
g = GMe/Re² --------------- euation 1
where,
g = acceleration due to gravity on surface of earth
G = Universal Gravitational Constant
Me = Mass of Earth
Re = Radius of Earth
Now, the the acceleration due to gravity on the surface of Kepler-62e is:
g' = GM'/R'² --------------- euation 1
where,
g' = acceleration due to gravity on surface of Kepler-62e
G = Universal Gravitational Constant
M' = Mass of Kepler-62e = 3.57 Me
R' = Radius of Kepler-62e = 1.61 Re
Therefore,
g' = G(3.57 Me)/(1.61 Re)²
g' = 1.38 GMe/Re²
using equation 1:
g' = 1.38 g
where,
g = 9.8 m/s²
Therefore,
g' = 1.38(9.8 m/s²)
<u>g' = 13.5 m/s²</u>