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2 years ago

Power is calculated by multiplying voltage by

1 answer:

5 0

If you're calculating the power of an athlete who is lifting weights,
or the power of a windmill that is pumping water from a well, or
the power of two horses turning millstones, then those electrical
units won't help at all.

But if you happen to be calculating the power delivered to an
electrical circuit or dissipated by an electrical device, then you
can use ...

(voltage) times (current)
or
(voltage)² divided by (resistance)
or
(current)² times (resistance) .

The choice just depends on which quantities you know
or can easily measure.

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What is the potential energy of a 25 kg bicycle resting at the top of a hill 3 m high? (Formula: PE = mgh)

Lisa [10]

Answer:

The answer would be 735J

Explanation:

PE=mgh

=(mass)(force of gravity)(height)

=(25kg)(9.8m/s^2)(3m)

=735J

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2 years ago

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Explanation:

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2 years ago

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Answer:

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2 years ago

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3 years ago

In an experiment designed to measure the strength of a uniform magnetic field produced by a set of coils, electrons are accelera

Arlecino [84]

Answer:

the magnitude of the magnetic field is 8.704 x 10⁻⁴ T

Explanation:

Given;

potential difference, V = 278 V

radius of the circular path, r = 6.46 cm = 0.0646 m

charge of electron, q = 1.60218 × 10⁻¹⁹ C

mass of electron, m = 9.10939 × 10⁻³¹ kg

The magnitude of the magnetic field is given as;

$B = \frac{M_e*v}{q*r}$

where;

B is the magnitude of the magnetic field

$M_e$ is mass of the electron

v is velocity of the electron

r is the radius of the circular path

q is charge of the electron

Determine velocity of the electron from kinetic energy equation;

$K = \frac{1}{2} M_ev^2\\\\Vq = \frac{1}{2} M_ev^2\\\\v^2 = \frac{2qV}{M_e} \\\\v = \sqrt{\frac{2qV}{M_e}} = \sqrt{\frac{2*1.602*10^{-19}*278}{9.109*10^{-31}}} = 9.8886*10^{6} \ m/s$

the magnitude of the magnetic field:

$B = \frac{M_e*v}{q*r} \\\\B = \frac{(9.109*10^{-31})*(9.8886*10^6)}{(1.602*10^{-19})*(0.0646)} = 8.704*10^{-4} \ T$

Therefore, the magnitude of the magnetic field is 8.704 x 10⁻⁴ T

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2 years ago