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3 years ago

According to legend, Galileo dropped two balls from the Tower of Pisa to see which would fall

Physics

1 answer:

Zanzabum3 years ago

7 0

Answer: 4.9 N

Explanation:

Weight $W$ is the force that gravity exerts on matter and changes depending on where the body is located. This means, the weight of an object on Earth will not be the same as the weight of the same object on the Moon or on Mars.

Well, in the case of Galileo, he performed his experiment on Earth. Hence, the acceleration due gravity is $g=9.8 m/s^{2}$ .

In addition, weight is mathematically expressed as:

$W=m.g$

Where $m=5 kg$ is the mass of the ball

Solving the equation:

$W=(5 kg)(9.8 m/s^{2})$

$W=4.9 N$ This is the weight of the ball

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3 years ago

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A ball has mass of 140g. what is the force to accelerate the ball at 25m/s

Fittoniya [83]

We know, F = m * a

Here, m = 140 g = 0.140 Kg

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It would be: F = 0.140 * 25 = 3.5 N

So your answer would be 3.5N

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3 years ago

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An astronaut has a mass of 50.0 kg on earth. what is her mass on the moon, where gravity is 1 6 that on earth?

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I believe the correct gravity on the moon is 1/6 of Earth. Take note there is a difference between 1 6 and 1/6.

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<span>Therefore if he has a mass of 50 kg on Earth, then he will also have a mass of 50 kg on moon.</span>

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4 years ago

How does the density of fluid affect the magnitude of buoyancy acting on an object immersed in it

Oksi-84 [34.3K]

Answer:

Explanation:

more the density , more will be the buoyant force acting on it , less the density less will be the buoyant force acting on it. This is why people float in dead sea and sink in other seas

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3 years ago

A 12.70 g bullet has a muzzle velocity (at the moment it leaves the end of a firearm) of 430 m/s when rifle with a weight of 25.

Norma-Jean [14]

Answer:

2.1844 m/s

Explanation:

The principle of conservation of momentum can be applied here.

when two objects interact, the total momentum remains the same provided no external forces are acting.

Consider the whole system , gun and bullet. as an isolated system, so the net momentum is constant. In particular before firing the gun, the net momentum is zero. The conservation of momentum,

$0=m_{bullet}*v_{bullet} + m_{rifle}*v_{rifle} \\$

assume the bullet goes to right side and the gravitational acceleration =10 $ms^{-2}$

so now the weight of the rifle= $\frac{25}{10}$

$0=m_{bullet}*v_{bullet} + m_{rifle}*v_{rifle} \\\\0=(12.70*10^{-3}) *430ms^{-1} +(\frac{25}{10} )*v_{rifle} \\v_{rifle} =-2.1844ms^{-1}$

this is a negative velocity to the right side. that means the rifle recoils to the left side

3 0

3 years ago