7. PE=0.5×700n/m×0.9m^2
0.9^2=0.81m
0.5×700×0.81= 283.5J
8. 2000=0.5×(x)×1.5m^2
1.5^2= 0.25
0.25×0.5=0.125
2000=0.125 (x)
2000/0.125=x
x=16000 n/m
9. 4000=0.5 (375 n/m)×(x)^2
0.5×187.5 (x)
4000/187.5=21.3333333333
fault-block mountains. hope this helps
Explanation:
no one is that I can get it to you tomorrow at the same time ago i used to
We make a graphic of this problem to define the angle.
The angle we can calculate through triangle relation, that is,
With this function we should only calculate the derivate in function of c
That is the rate of change of 
.
b) At this point we need only make a substitution of 0 for c in the equation previously found.
Hence we have finally the rate of change when c=0.
According to the law of conservation of energy,
A. an object loses most of its energy as friction
<u>B. the total amount of energy for a system stays the same</u>
Energy is never lost due to the law of conservation
C. the potential energy of an object is always greater than its kinetic energy
D. the kinetic energy of an object is always greater than its potential energy
