(a) Find the linear equation that relates the temperature t and the number of chirps per minute n.
If the equation is linear, then the equation should have the form of t = mn + b
m = (80 - 70) / (168 - 120) = 5/24
t = 5/24n + b
70 = 5/24(120) + b
b = 45
t = 5/24 n + 45
<span>(b) If the crickets are chirping at 138 chirps per minute, estimate the temperature. (Round your answer to the nearest degree.)
</span><span>t = 5/24 n + 45
</span><span>t = 5/24 (138) + 45 = 74 </span>°F
If you consult the unit circle, you will see that:

3pi/4 in degrees is 3pi/4 * 180/pi = 3/4 * 180 = 135 degrees. And please refer to the attachment to how you can obtain the values above.
Now, lets multiply it together.

So, <span>cos(3pi/4)sin(3pi/4) =
-1/2</span>
Answer:
In the picture above
Step-by-step explanation:
I think it's a clear explanation.
The answer is 12/14 just times 2 to it i think