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barxatty [35]
2 years ago
13

For an aqueous solution of sucrose (C12H22O11), determine: (a) the molarity of 3.30 L of a solution that contains 225.0 g of suc

rose M (b) the volume of this solution that would contain 4.30 mole of sucrose L (c) the number of moles of sucrose in 1.00 L of this solution mol C12H22O11
Chemistry
1 answer:
dusya [7]2 years ago
8 0

Answer:

a) Molarity = 0.199M

b) 21.6L of solution

c) 0.199 moles of sucrose in 1L

Explanation:

a) Molarity is the ratio of moles of solute (sucrose) in volume of solution (3.30L):

<em>Moles sucrose -Molar mass: 342,3g/mol-:</em>

225.0g * (1mol / 342,2965g) = 0.6573 moles

Molarity = 0.6573 moles / 3.30L

<h3>Molarity = 0.199M</h3><h3 />

b) 0.199M means 0.199 moles in 1L. 4.30 moles are in:

4.30 mol * (1L / 0.199mol) = 21.6L of solution

c) By definition, there are 0.199 moles of sucrose in 1L. This is the meaning of 0.199M

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LuckyWell [14K]

Answer:

0.0984mol of F2

Explanation:

The equation for the reaction is given below:

Kr + F2 → KrF2

Let us convert 12g of KrF2 to mole. This is illustrated below

Molar Mass of KrF2 = 84 + (2x19) = 84 + 38 = 122g/mol

Mass of KrF2 = 12g

Number of mole = Mass /Molar Mass

Number of mole of KrF2 = 12/122 = 0.0984mol

From the equation,

1mole of F2 produced 1mole of KrF2.

Therefore 0.0984mol of F2 will produce 0.0984mol of KrF2

7 0
3 years ago
A sample of gas is at 273°K and 2.00 atm with a volume of 6.00 liters. When the gas is compressed to 3.00 liters and the pressur
horrorfan [7]

Answer: 0.00488K

Explanation: using the general gas equation

(P1V1)/T1 =(P2V2)/T1

Substitute

2*6/273= 3*3/T

Simplify

T= 0.00488°K

3 0
3 years ago
In the chemical reaction:
velikii [3]

Taking into account the reaction stoichiometry and definition of limiting reactant, AgNO₃ will be the limiting reagent.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

Cu + 2 AgNO₃  → 2 Ag + Cu(NO₃)₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • Cu: 1 mole
  • AgNO₃: 2 moles
  • Ag: 2 moles
  • Cu(NO₃)₂: 1 mole

<h3>Limiting reagent</h3>

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

<h3>Limiting reagent in this case</h3>

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 1 mole of Cu reacts with 2 moles of AgNO₃, 1.8 moles of Cu reacts with how many moles of AgNO₃?

amount of moles of AgNO_{3} =\frac{1.8 moles of Cux2 moles of AgNO_{3} }{1 mole of Cu}

<u><em>amount of moles of AgNO₃= 3.6 moles</em></u>

But 3.6 moles of AgNO₃ are not available, 2 moles are available. Since you have less moles than you need to react with 1.8 moles of Cu, AgNO₃ will be the limiting reagent.

<h3>Summary</h3>

In summary, AgNO₃ will be the limiting reagent.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

#SPJ1

8 0
1 year ago
Under what conditions does the hydrolysis of an amide bond occur?
Mademuasel [1]
Hi.

I did some digging and I think I found what you're looking for.

I found this on Q(uizlet)

basic or acidic conditions and the reactants must be heated.

~
5 0
2 years ago
4. A sign in a town gives the speed limit at 50.00 km/hr. What is this speed in cm/sec?​
ivanzaharov [21]

sorry but if you are looking for an answer I don't know one. :(

3 0
2 years ago
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