Answer:
I think A. I had a similar question
Explanation:
Answer:
T_2= 234.37 K
Explanation:
According to Claperyon, we know that
P_1= Atmospheric pressure 760 mm Hg
P_2 = pressure at the bottom of the column
= 10×10^3 mm of Hg+ 760 mm of Hg
= 10760 mm of Hg
now,
P_2-P_1= 10760-760= 10^4 mm
P_2-P_1 ( in pascals) = 10^4× 133.322= 1333220 mm
the enthalpy of fusion (ΔH-fus) of mercury is 2.292 KJ/mol
use the above equation to calculate ΔT as follows
therefore, T_2= 234.37 K
Explanation:
It is given that,
Diameter of the circular loop, d = 1.5 cm
Radius of the circular loop, r = 0.0075 m
Magnetic field,
(A) We need to find the current in the loop. The magnetic field in a circular loop is given by :
I = 32.22 A
(b) The magnetic field on a current carrying wire is given by :
r = 0.00238 m
Hence, this is the required solution.
Answer: 17.03 rad/s^2
Explanation: One of the equation of motion that defines a circular motion with constant acceleration is given below as
ω = ω0 + αt
Where ω = final angular velocity = 9.3 rev/s
ω0 = initial angular velocity = 7.1 rev/s
α = angular acceleration = ?
t = time taken = 6.0s
By substituting the parameters, we have that
9.3 = 7.1 +α(6)
9.3 - 7.1 = 6α
16.3 = 6α
α = 16.3/6
α = 2.71 rev/s^2
We can also give the answer in rad/s^2 ( another unit of angular acceleration) by multipying by 2π
Hence, α = 2.71 × 2π , where π = 3.142
α = 17.03 rad/s^2
The type of bond that connects water molecules together is called covalent bond~