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erik [133]
3 years ago
12

A Frisbee of radius 0.15 m is accelerating at a constant rate from 7.1 revolutions per second to 9.3 revolutions per second in 6

.0 s. What is its angular acceleration?
Physics
1 answer:
Greeley [361]3 years ago
7 0

Answer: 17.03 rad/s^2

Explanation: One of the equation of motion that defines a circular motion with constant acceleration is given below as

ω = ω0 + αt

Where ω = final angular velocity = 9.3 rev/s

ω0 = initial angular velocity = 7.1 rev/s

α = angular acceleration = ?

t = time taken = 6.0s

By substituting the parameters, we have that

9.3 = 7.1 +α(6)

9.3 - 7.1 = 6α

16.3 = 6α

α = 16.3/6

α = 2.71 rev/s^2

We can also give the answer in rad/s^2 ( another unit of angular acceleration) by multipying by 2π

Hence, α = 2.71 × 2π , where π = 3.142

α = 17.03 rad/s^2

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attashe74 [19]
PE = mgh
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      = 7*10*2
 
       = 140 Joules.


5 0
3 years ago
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A loop of wire is carrying current of 2 A . The radius of the loop is 0.4 m. What is the magnetic field at a distance 0.09 m alo
HACTEHA [7]

Answer:

B=2.91\ \mu T

Explanation:

Given that,

The current in the loop, I = 2 A

The radius of the loop, r = 0.4 m

We need to find the magnetic field at a distance 0.09 m along the axis and above the center of the loop. The formula for the magnetic field at some distance is given as follows :

B=\dfrac{\mu_o}{4\pi }\dfrac{2\pi r^2 I}{(r^2+d^2)^{3/2}}

Put all the values,

B=10^{-7}\times \dfrac{2\pi \times 0.4^2 \times 2}{(0.4^2+0.09^2)^{3/2}}\\\\=2.91\times 10^{-6}\ T\\\\or\\\\B=2.91\ \mu T

So, the required magnetic field is equal to 2.91\ \mu T.

3 0
2 years ago
As an object moves along the x axis, many measurements are made of its position, enough to generate a smooth, accurate graph of
Bas_tet [7]
The best and most correct answers among the choices provided by your question are he second and third choices. 
<span>The velocity at any instant the average velocity during some time interval cannot be obtained from the graph alone.</span>


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
6 0
3 years ago
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What is the velocity of a proton that has been accelerated by a potential difference of 15 kV? (i)\:\:\:\:\:9.5\:\times\:10^5\:m
andre [41]

Answer:

Velocity of a proton, v=1.7\times 10^6\ m/s    

Explanation:

It is given that,

Potential difference, V=15\ kV=15\times 10^3\ V

Let v is the velocity of a proton that has been accelerated by a potential difference of 15 kV.

Using the conservation of energy as :

\dfrac{1}{2}mv^2=qV

q is the charge of proton

m is the mass of proton

v=\sqrt{\dfrac{2qV}{m}}

v=\sqrt{\dfrac{2\times 1.6\times 10^{-19}\ C\times 15\times 10^3\ V}{1.67\times 10^{-27}\ kg}

v=1695361.75\ m/s

v=1.69\times 10^6\ m/s

or

v=1.7\times 10^6\ m/s

So, the velocity of a proton is 1.7\times 10^6\ m/s. Hence, this is the required solution.

8 0
3 years ago
Does a black hole have 2 sides that pull light together?
Ostrovityanka [42]
Check this Light doesn't have mass or gravity right?
So if it doesn't have mass or gravity so light can only affect objects with mass
Does that make sense?
The black hole has gravity and remember light doesn't have gravity so does it affect the light?
To answer that yes, and since light doesn't have gravity it gets "pulled" into the black hole

I hope this helps you

8 0
3 years ago
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