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erik [133]
2 years ago
12

A Frisbee of radius 0.15 m is accelerating at a constant rate from 7.1 revolutions per second to 9.3 revolutions per second in 6

.0 s. What is its angular acceleration?
Physics
1 answer:
Greeley [361]2 years ago
7 0

Answer: 17.03 rad/s^2

Explanation: One of the equation of motion that defines a circular motion with constant acceleration is given below as

ω = ω0 + αt

Where ω = final angular velocity = 9.3 rev/s

ω0 = initial angular velocity = 7.1 rev/s

α = angular acceleration = ?

t = time taken = 6.0s

By substituting the parameters, we have that

9.3 = 7.1 +α(6)

9.3 - 7.1 = 6α

16.3 = 6α

α = 16.3/6

α = 2.71 rev/s^2

We can also give the answer in rad/s^2 ( another unit of angular acceleration) by multipying by 2π

Hence, α = 2.71 × 2π , where π = 3.142

α = 17.03 rad/s^2

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Power is equal to energy per unit time. In this case, power is proportional to energy while is inversely proportional to time,on the other hand. Given the two swimmers exerts same amount of energy but the faster swimmer just does things in faster time, then the faster swimmer should develop more power from shorter time
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3 years ago
Two everyday examples of a starting motion
Tasya [4]
Pushing, pulling is the answer
8 0
3 years ago
A. How many atoms of helium gas fill a spherical balloon of diameter 29.6 cm at 19.0°C and 1.00 atm? b. What is the average kine
Korolek [52]

Answer:

a) 3.39 × 10²³ atoms

b) 6.04 × 10⁻²¹ J

c) 1349.35 m/s

Explanation:

Given:

Diameter of the balloon, d = 29.6 cm = 0.296 m

Temperature, T = 19.0° C = 19 + 273 = 292 K

Pressure, P = 1.00 atm = 1.013 × 10⁵ Pa

Volume of the balloon = \frac{4}{3}\pi(\frac{d}{2})^3

or

Volume of the balloon = \frac{4}{3}\pi(\frac{0.296}{2})^3

or

Volume of the balloon, V = 0.0135 m³

Now,

From the relation,

PV = nRT

where,

n is the number of moles

R is the ideal gas constant = 8.314  kg⋅m²/s²⋅K⋅mol

on substituting the respective values, we get

1.013 × 10⁵ × 0.0135 = n × 8.314 × 292

or

n = 0.563

1 mol = 6.022 × 10²³ atoms

Thus,

0.563 moles will have = 0.563 × 6.022 × 10²³ atoms = 3.39 × 10²³ atoms

b) Average kinetic energy = \frac{3}{2}\times K_BT

where,

Boltzmann constant, K_B=1.3807\times10^{-23}J/K

Average kinetic energy = \frac{3}{2}\times1.3807\times10^{-23}\times292

or

Average kinetic energy = 6.04 × 10⁻²¹ J

c) rms speed = \frac{3RT}{m}

where, m is the molar mass of the Helium = 0.004 Kg

or

rms speed = \frac{3\times8.314\times292}{0.004}

or

rms speed = 1349.35 m/s

5 0
3 years ago
A 70 kg hunter, standing on frictionless ice, shoots a 42 g bullet horizontally at a speed of 590 m/s . Part A Part complete Wha
Kisachek [45]

Answer:

The recoil velocity is 0.354 m/s.

Explanation:

Given that,

Mass of hunter = 70 kg

Mass of bullet = 42 g = 0.042 kg

Speed of bullet = 590 m/s

We need to calculate the recoil speed of hunter

Using conservation of momentum

m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}

Where,m_{1} = mass of hunter

m_{2} = mass of bullet

u = initial velocity

v = recoil velocity

Put the value in the equation

0+0=70\times v_{1}+0.042\times590

v_{1}=-\dfrac{0.042\times590}{70}

v=-0.354\ m/s

Hence, The recoil velocity is 0.354 m/s.

8 0
3 years ago
I have a big test coming up and these two questions i don't understand: Choose the best answer: A device that transforms mechani
Jlenok [28]
1. B- electric generator

Although its really sometimes called an AC generator.

- i hoped i helped u :)





3 0
3 years ago
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