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Margarita [4]
3 years ago
7

The enthalpy of fusion of mercury is 2.292 kJ mol-1 at its normal freezing point of 234.3 K; the change in molar volume on melti

ng is +0.517 cm3 mol-1. At what temperature will the bottom of a column of mercury (mass density 13.6 g cm-3) of height 10 m be expected freeze? The pressure at a depth d in a fluid with mass density rho is rhogd, where g is the acceleration of free fall, 9.81 ms-2.
Physics
1 answer:
aev [14]3 years ago
6 0

Answer:

T_2= 234.37 K

Explanation:

According to Claperyon, we know that

P_2-P_1= \frac{\Delta H_{fus}}{\Delta V}\times\frac{T_1}{T_2}

P_1= Atmospheric pressure 760 mm Hg

P_2 = pressure at the bottom of the column

= 10×10^3 mm of Hg+ 760 mm of Hg

= 10760 mm of Hg

now,

P_2-P_1= 10760-760= 10^4 mm

P_2-P_1 ( in pascals) = 10^4× 133.322= 1333220 mm

the enthalpy of fusion (ΔH-fus) of mercury is 2.292 KJ/mol

use the above equation to calculate ΔT as follows

1333220= \frac{2292}{0.517\times10^{-6}}\times ln\frac{T_2}{234.3K}

therefore, T_2= 234.37 K

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Graph:

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