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Tresset [83]
2 years ago
9

For the following experiments, identify the independent variable and the dependent variable:

Chemistry
1 answer:
faust18 [17]2 years ago
3 0

Answer:

A) IV: number of hours DV: score

Explanation:

Coz,

IV- is the variable that u change

DV- is the variable that u test or measure

In this case, we need to change the hours of studying to see how studying for different hours [1 hr, 2hr, etc (( Independant variable coz we're changing the no. of hours)) ] is going to affect the student's score, and in the end, we are measuring the score of each student [this is the dependant variable].

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What is the salt that is produced when calcium hydroxide (Ca(OH)2) reacts with sulfuric acid (H2SO4)? CaSH2Ca H2O CaSO4
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H2SO4+CA[OH]2=CASO4+2H2O
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3 years ago
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A materials scientist has created an alloy containing aluminum, copper, and zinc, and wants to determine the percent composition
liubo4ka [24]

Answer:

0.8749 grams of hydrogen gas was formed from the reaction.

Explanation:

P = Pressure of hydrogen gad= 744 Torr = 0.98 atm

(1 atm = 760 Torr)

V = Volume of hydrogen gas= 11 L

n = number of moles of hydrogen gas= ?

R = Gas constant = 0.0821 L.atm/mol.K

T = Temperature of vapor = 27.0 °C = 300.15 K

Putting values in above equation, we get:

Using an ideal gas equation:

PV=nRT

n=\frac{PV}{RT}=\frac{0.98 atm\times 11 L}{0.0821 L atm/mol K\times 300.15 K}

n = 0.4374 moles

Mass of 0.4374 moles of hydrogen gas:

0.4374 mol × 2 g/mol = 0.8749 g

0.8749 grams of hydrogen gas was formed from the reaction.

7 0
3 years ago
I dunno which one it is could someone help please?​
alex41 [277]

Answer: B. photosynthesis

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5 0
3 years ago
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A container holds 6.4 moles of gas. Hydrogen gas makes up 25% of the total moles in the container. If the total pressure is 1.24
Degger [83]
  The   partial  pressure of hydrogen is 0.31  atm

calculation

find the number of  hydrogen   moles the container, that is

25/100  x 6.4  =1.6 moles of hydrogen

find the  partial pressure for hydrogen  in 1.6 moles

that is   6.4  moles=  1.24 atm
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by  cross  multiplication

1.6moles  x1.24  atm/ 6.4 moles=  0.31 atm
6 0
3 years ago
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Let's eliminate these one by one.
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