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aleksley [76]
2 years ago
7

Based on electronegativity, select the molecule with the most ionic character. Group of answer choices SBr2 OBr2 SeCl2 TeI2 SCl2

Chemistry
1 answer:
Basile [38]2 years ago
4 0

Answer:

OBr₂

Explanation:

<em>The ionic character depends on the difference of electronegativity between the elements. The higher ΔEN, the greater the ionic character.</em>

SBr₂

ΔEN = |EN(S)-EN(Br)| = |2.5-2.8| = 0.3

OBr₂

ΔEN = |EN(O)-EN(Br)| = |3.5-2.8| = 0.7

SeCl₂

ΔEN = |EN(Se)-EN(Cl)| = |2.4-3.0| = 0.6

TeI₂

ΔEN = |EN(Te)-EN(I)| = |2.1-2.5| = 0.4

SCl₂

ΔEN = |EN(S)-EN(Cl)| = |2.5-3.0| = 0.5

OBr₂ is the molecule with the most ionic character.

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Answer:

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Explanation:

We present the reaction:

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As we do not have data from the SO₂, we assume this as the excess reagent. We convert the mass of carbon to moles:

70.8 g / 12 g/mol = 5.9 moles

Ratio is 5:1, so 5 moles of carbon react to produce 1 mol of CS₂

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3 0
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2 years ago
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3 years ago
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Hope this answers the question.  Have a nice day.


7 0
3 years ago
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