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aleksley [76]
3 years ago
7

Based on electronegativity, select the molecule with the most ionic character. Group of answer choices SBr2 OBr2 SeCl2 TeI2 SCl2

Chemistry
1 answer:
Basile [38]3 years ago
4 0

Answer:

OBr₂

Explanation:

<em>The ionic character depends on the difference of electronegativity between the elements. The higher ΔEN, the greater the ionic character.</em>

SBr₂

ΔEN = |EN(S)-EN(Br)| = |2.5-2.8| = 0.3

OBr₂

ΔEN = |EN(O)-EN(Br)| = |3.5-2.8| = 0.7

SeCl₂

ΔEN = |EN(Se)-EN(Cl)| = |2.4-3.0| = 0.6

TeI₂

ΔEN = |EN(Te)-EN(I)| = |2.1-2.5| = 0.4

SCl₂

ΔEN = |EN(S)-EN(Cl)| = |2.5-3.0| = 0.5

OBr₂ is the molecule with the most ionic character.

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The decreasing order of first ionization energy: x > y > z

Explanation:

Ionization energy refers to the energy needed to completely pull out an electron from the valence shell of a neutral gaseous atom.

First ionization energy is the energy involved in the removal of first valence electron.

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<u><em>Whereas, across a period, as atomic radius of elements decreases, the ionization energy increases.</em></u>

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Thus, the increasing order of atomic radius: Se < Ge < In < Cs

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PART (B):

Given elements:

element x: radius = 110 pm

element y: radius = 199 pm

element z: radius = 257 pm

Thus, the increasing order of atomic radius: x < y < z

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