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3 years ago

Based on electronegativity, select the molecule with the most ionic character. Group of answer choices SBr2 OBr2 SeCl2 TeI2 SCl2

Chemistry

1 answer:

Basile [38]3 years ago

4 0

Answer:

OBr₂

Explanation:

<em>The ionic character depends on the difference of electronegativity between the elements. The higher ΔEN, the greater the ionic character.</em>

SBr₂

ΔEN = |EN(S)-EN(Br)| = |2.5-2.8| = 0.3

OBr₂

ΔEN = |EN(O)-EN(Br)| = |3.5-2.8| = 0.7

SeCl₂

ΔEN = |EN(Se)-EN(Cl)| = |2.4-3.0| = 0.6

TeI₂

ΔEN = |EN(Te)-EN(I)| = |2.1-2.5| = 0.4

SCl₂

ΔEN = |EN(S)-EN(Cl)| = |2.5-3.0| = 0.5

OBr₂ is the molecule with the most ionic character.

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Answer: -

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