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Stels [109]
3 years ago
11

The mass of an object is the

Chemistry
2 answers:
Scorpion4ik [409]3 years ago
8 0

Answer:the amount of matter the object contains

Explanation:

soldi70 [24.7K]3 years ago
3 0

Answer:

the measurement of how much matter is in an object

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vlabodo [156]

Answer: Wave A is a lower frequencey and Wave B is a higher frequencey

Explanation:

this should help u with question 1 and 2

6 0
4 years ago
Which element is a metalloid out of aluminum, arsenic, carbon, and helium?
Katyanochek1 [597]

Answer:

arsenic

Explanation:helium is a gas and aluminum is a etal and carbon is not a maetalloid

6 0
3 years ago
100 ml of gaseous hydrocarbon consumes 300
zhenek [66]

The answer would be a. C2H4(ethylene)

1C2H4+3O2~>2CO2+2H2O

6 0
3 years ago
Read 2 more answers
What is the limiting reactant when 20g CH4 react with 15g H20?
Art [367]

Answer:

H₂O.

Explanation:

  • It is clear from the balanced equation:

<em>CH₄ + 2H₂O → CO₂ + 4H₂.</em>

that 1.0  mole of CH₄ reacts with 2.0 moles of H₂O to produce 1.0 mole of CO₂ and 4.0 moles of H₂.

  • To determine the limiting reactant, we should calculate the no. of moles of (20 g) CH₄ and (15 g) H₂O using the relation:

<em>n = mass/molar mass</em>

<em></em>

no. of moles of CH₄ = mass/molar mass = (20 g)/(16 g/mol) = 1.25 mol.

no. of moles of H₂O = mass/molar mass = (15 g)/(18 g/mol) = 0.833 mol.

  • <em>from the balanced reaction, 1.0  mole of CH₄ reacts with 2.0 moles of H₂O.</em>

So, from the calculated no. of moles: 0.4167 mole of CH₄ reacts completely with 0.833 mole of H₂O and the remaining of CH₄ will be in excess.

<u><em>So, the limiting reactant is H₂O.</em></u>

4 0
3 years ago
The empirical formula of a compound is CH. At 200 degree C, 0.145 g of this compound occupies 97.2 mL at a pressure of 0.74 atm.
Vladimir [108]

Answer:

The molecular formula = C_{6}H_{6}

Explanation:

Given that:

Mass of compound, m = 0.145 g

Temperature = 200 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (200 + 273.15) K = 473.15 K

V = 97.2 mL = 0.0972 L

Pressure = 0.74 atm

Considering,  

n=\frac{m}{M}

Using ideal gas equation as:

PV=\frac{m}{M}RT

where,  

P is the pressure

V is the volume

m is the mass of the gas

M is the molar mass of the gas

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the values in the above equation as:-

0.74\times 0.0972=\frac{0.145}{M}\times 0.0821\times 473.15

M=78.31\ g/mol

The empirical formula is = CH

Molecular formulas is the actual number of atoms of each element in the compound while empirical formulas is the simplest or reduced ratio of the elements in the compound.

Thus,  

Molecular mass = n × Empirical mass

Where, n is any positive number from 1, 2, 3...

Mass from the Empirical formula = 12 + 1 = 13 g/mol

Molar mass = 78.31 g/mol

So,  

Molecular mass = n × Empirical mass

78.31 = n × 13

⇒ n ≅ 6

The molecular formula = C_{6}H_{6}

6 0
3 years ago
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