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Citrus2011 [14]
3 years ago
7

80g of sodium hydroxide reacts with excess sulfuric acid to produce 142g of sodium sulfate. What mass of sodium hydroxide would

be needed in order to make 50g of sodium sulfate?
Chemistry
1 answer:
Ostrovityanka [42]3 years ago
6 0

Answer:

Mass of sodium hydroxide needed  = 28.2 g

Explanation:

Given data:

Mass of sodium hydroxide = 80 g

Mass of sodium sulfate produced = 142 g

Mass of sodium hydroxide needed = ?

Mass of sodium sulfate produced = 50 g

Solution:

Mass of sodium sulfate produced / Mass of sodium hydroxide = Mass of sodium sulfate produced / x

142 g/ 80 g = 50 g / x

x = 50 g × 80 g / 142 g

x =4000 g/ 142

x = 28.2 g

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ATP is a molecule used for energy transport inside the cell. The components of ATP are a nitrogen-containing base, a pentose sug
Zinaida [17]

Answer:

nucleic acid

Explanation:

ATP -

In the living organisms it is a very important source of energy for various biological processes like chemical synthesis , nerve impulse propagation and contraction of muscles , is referred to as Adenosine triphosphate ( ATP ) .

ATP is a nucleic acid , which is a single chain nucleotide , which is composed of ribose sugar along with three phosphate groups .

ATP is also known as the battery of the cell.

Hence , from the given information of the question ,

The correct term is nucleic acid.

5 0
3 years ago
If the gas in the piston above has a volume of 20.0 L at a temperature of 25 degrees C, what is the volume of that gas when it i
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Answer:

15.98 L

Explanation:

3 0
3 years ago
Read 2 more answers
How many atoms are there in 3.559*10^-6 mol of krypton?
algol [13]

Answer:

The answer is

<h2>2.143 \times  {10}^{18}  \:  \: atoms</h2>

Explanation:

To find the number of atoms given the number of moles we use the formula

N = n × L

where

N is the number of entities

n is the number of moles

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question

n = 3.559 \times  {10}^{ - 6}  \: mol

Substitute the values into the above formula and solve

That's

<h3>N  = 3.559 \times  {10}^{ - 6}  \times 6.02 \times  {10}^{23}  \\  = 2.1425 \times  {10}^{18}</h3>

We have the final answer as

<h3>N  = 2.143 \times  {10}^{18}  \:  \: atoms</h3>

Hope this helps you

3 0
3 years ago
********WORTH 25 POINTS******What are 3 examples of Chemical weathering?
Scrat [10]

Answer:

Carbonation. When you think of carbonation, think carbon

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Explanation:

5 0
3 years ago
For some hypothetical metal, the equilibrium number of vacancies at 600°C is 1 × 1025 m-3. If the density and atomic weight of t
makvit [3.9K]

Answer:

\frac{N_{v}}{N}=1.92*10^{-4}

Explanation:

First of all we need to find the amount of atoms per volume (m³). We can do this using the density and the molar mass.

7.40 \frac{g}{cm^{3}}*\frac{1mol}{85.5 g}*\frac{6.023*10^{23}atoms}{1mol}*\frac{1000000 cm^{3}}{1m^{3}}=5.21*10^{28}\frac{atoms}{m^{3}}

Now, the fraction of vacancies is equal to the N(v)/N ratio.

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Therefore:  

The fraction of vacancies at 600 °C will be:

\frac{N_{v}}{N}=\frac{1*10^{25}}{5.21*10^{28}}  

\frac{N_{v}}{N}=1.92*10^{-4}

I hope it helps you!

 

7 0
3 years ago
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