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boyakko [2]
3 years ago
10

Triangle J K L is shown. Angle K J L is 58 degrees and angle J L K is 38 degrees. The length of J K is 2.3 and the length of J L

is k.
Law of sines: StartFraction sine (uppercase A) Over a EndFraction = StartFraction sine (uppercase B) Over b EndFraction = StartFraction sine (uppercase C) Over c EndFraction

Which measures are accurate regarding triangle JKL? Select two options.

m∠K = 94°
k ≈ 3.7 units
k ≈ 4.6 units
KL ≈ 2.5 units
KL ≈ 3.2 units
Mathematics
2 answers:
Romashka-Z-Leto [24]3 years ago
5 0
Try 3.7 and see it u got it
yKpoI14uk [10]3 years ago
5 0

Answer:

C and D 3.7 and 2.5

Step-by-step explanation:

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A company rents out 13 food booths and 27 game booths at the county fair. The fee for a food booth
horsena [70]

Answer:

50+(7d*13)+80+(9d*27)

Step-by-step explanation:

So, there are 13 food booths and each food booth is $50 plus $7 per day.

There are 27 game booths and each game booth is $80 plus $9 per day.

Lets make a short equation for each of the booths.

50+(7d*13)

80+(9d*27)

Lets combine both of the sentences.

50+(7d*13)+80+(9d*27)

So, my expression would be 50+(7d*13)+80+(9d*27).

8 0
3 years ago
-4x + 6 + 2x + 5, Solve for X
pychu [463]
-4x + 2x = -2x
6 + 5 = 11
Therefore, 11 - 2x = 0
11 = 2x
x = 11/2 = 5.5
8 0
3 years ago
Find the median and mean of the data which reflects the best measure of the center
galben [10]

Answer:

The mean reflects the best measure of the center

Step-by-step explanation:

12, 13, 13, 14, 21, 22, 23

Median: 14

Mean: 16.86

The mean reflects the best measure of the center

7 0
4 years ago
What is the midpoint of A (-2,-4) and (4,-7)
Sloan [31]
The answer/midpoint is 1,5.5
5 0
3 years ago
Type the correct answer in each box. The reflection of point S across the y-axis is point . The reflection of point Q across the
tresset_1 [31]

Answer:

S' = (-5,-5)

Q"=(-5,-5)

Step-by-step explanation:

Given

S = (5,-5)

Q= (5,5)

Solving (a): Reflect S across y-axis

The rule to reflect across y-axis is:

(x,y) \to (-x,y)

So, we have:

S(5,-5) \to S'(-5,-5)

Hence:

S' = (-5,-5)

Solving (b): Reflect Q across x and y-axis

The rule to reflect across x-axis is:

(x,y) \to (x,-y)

So:

Q(5,5) \to Q'(5,-5)

The rule to reflect across y-axis is:

(x,y) \to (-x,y)

So:

Q'(5,-5) \to Q"(-5,-5)

Hence:

Q"=(-5,-5)

6 0
3 years ago
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