Answer:
ok so umm i dont get what ur looking for?
Step-by-step explanation:
Answer:
A(t) = 300 -260e^(-t/50)
Step-by-step explanation:
The rate of change of A(t) is ...
A'(t) = 6 -6/300·A(t)
Rewriting, we have ...
A'(t) +(1/50)A(t) = 6
This has solution ...
A(t) = p + qe^-(t/50)
We need to find the values of p and q. Using the differential equation, we ahve ...
A'(t) = -q/50e^-(t/50) = 6 - (p +qe^-(t/50))/50
0 = 6 -p/50
p = 300
From the initial condition, ...
A(0) = 300 +q = 40
q = -260
So, the complete solution is ...
A(t) = 300 -260e^(-t/50)
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The salt in the tank increases in exponentially decaying fashion from 40 grams to 300 grams with a time constant of 50 minutes.
Answer:
Step-by-step explanation:
<u>Below numbers are divisible by the number of students:</u>
<u>Lets find GCF of 24 and 36:</u>
- 24 = 2*2*2*3
- 36 = 2*2*3*3
- GCF(24,36) = 2*2*3 = 12
The largest possible number of students is 12
Answer:
20%
Step-by-step explanation:
4+3+7=14
14÷7=2
2×10=20
If I am wrong please tell me I haven't had to do this me method in 3 years
The intercept can be found when all other variables are equated to zero.
x-intercept when y = 0 and z = 0: 8x + 6*0 + 3*0 = 24 gives x = 3
y-intercept when x = 0 and z = 0: 8*0 + 6y + 3*0 = 24 gives y = 4
z-intercept when x = 0 and y = 0: 8*0 + 6*0 + 3z = 24 gives z = 8
The intercepts are (3, 0, 0), (0, 4, 0), and (0, 0, 8).
