-25=-4r+5
Subtract 5 to each side
-25-5=-4r+5-5
-30=-4r
Divided -4 to each side
-30/-4=-4r/-4
7.5=r
Check:
-25=-4r+5
Substitute r with 7.5
-25=-4(7.5)+5
-25=-30+5
-25=-25. As a result, r=7.5. Hope it help!
1 is 39. J don’t know about 2 and 3 though:(
The length of ladder is 30 ft.
<h3>How can the feet that made up the side of the building is the top of the ladder be known ?</h3>
The formula below can be used in solving the problem
Tan (∅)= 
∅=70°
opposite = BC
Adjacent = 12 ft
70°= opposite/ 12
opposite= 32.96 ft
Therefore, The length of ladder is 30 ft.
NOTE; Since the actual diagram can not be found i solved another on on the same topic
Learn more about Trigonometry on:
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CHECK COMPLETE QUESTION BELOW:
Consider the diagram shown where a ladder is leaning against the side of a building. the base of the ladder is 12ft from the building. how long is the ladder? (to the nearest ft)
a. 25ft
b. 30ft
c. 35ft
d. 40ft
3/10 of the time = time spent on practicing warm up routines...
Time spent = 15 hours
remember that 'of' is usually multiply (x)
so ---- 3/10 x 15 =4.5 hrs
Hope this helps
Answer:
Step-by-step explanation:
Assuming there is a punitive removal of one point for an incorrect response.
Five undiscernable choices: 20% chance of guessing correctly -- Expectation: 0.20*(1) + 0.80*(-1) = -0.60
Four undiscernable choices: 25% chance of guessing correctly -- Expectation: 0.25*(1) + 0.75*(-1) = -0.50
I'll use 0.33 as an approzimation for 1/3
Three undiscernable choices: 33% chance of guessing correctly -- Expectation: 0.33*(1) + 0.67*(-1) = -0.33 <== The approximation is a little ugly.
Two undiscernable choices: 50% chance of guessing correctly -- Expectation: 0.50*(1) + 0.50*(-1) = 0.00
And thus we see that only if you can remove three is guessing neutral. There is no time when guessing is advantageous.
One Correct Answer: 100% chance of guessing correctly -- Expectation: 1.00*(1) + 0.00*(-1) = 1.00
